Organic Chemistry
12th Edition
ISBN: 9781118875766
Author: T. W. Graham Solomons, Craig B. Fryhle, Scott A. Snyder
Publisher: WILEY
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Textbook Question
Chapter 19, Problem 54P
The Perkin condensation is an aldol-type condensation in which an
(a) Outline the Perkin condensation that takes place when benzaldehyde reacts with propanoic anhydride in the presence of potassium propanoate.
(b) How would you use a Perkin condensation to prepare p-chlorocinnamic acid,
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2
H3C
H3C
H
C→XT
OH
H3C
The aldol reaction is a carbonyl condensation reaction between two carbonyl partners and involves a combination of nucleophilic addition
and a-substitution steps. One partner is converted into an enolate ion nucleophile and adds to the electrophilic carbonyl group of the
second partner. In the classic aldol reaction, the carbonyl partners are aldehydes or ketones, although aldehydes are more reactive. The
product is a ß-hydroxy carbonyl compound.
base
:0:
OH
H
H
Under reaction conditions slightly more vigorous than those employed for the aldol reaction, the ß-hydroxyl group is eliminated in an E1cB
dehydration to give an a,ß-unsaturated carbonyl compound.
Draw curved arrows to show the movement of electrons in this step of the mechanism.
Arrow-pushing Instruct ns
H3C
heat
OH
H3C
:0:
H
+ H₂O
H
2
Moin
H3C
H
H₂C
C⇒x=
base
:0:
OH
Hori
H3C
H.
The aldol reaction is a carbonyl condensation reaction between two carbonyl partners and involves a combination of nucleophilic addition and
a-substitution steps. One partner is converted into an enolate ion nucleophile and adds to the electrophilic carbonyl group of the second
partner. In the classic aldol reaction, the carbonyl partners are aldehydes or ketones, although aldehydes are more reactive. The product is a
B-hydroxy carbonyl compound.
Under reaction conditions slightly more vigorous than those employed for the aldol reaction, the ß-hydroxyl group is eliminated in an E1cB
dehydration to give an a,ß-unsaturated carbonyl compound.
Draw curved arrows to show the movement of electrons in this step of the mechanism.
Arrow-pushing Instructions
H₂C
Ἡ
:0:
heat
H
Home
H3C
+ H₂O
The product of this chloromethylation can be converted to piperonal, which is used in perfumery and in artificial cherry and vanilla flavors. How might the CH2Cl group of the chloromethylation product be converted to a CHO group?
Chapter 19 Solutions
Organic Chemistry
Ch. 19 - PRACTICE PROBLEM 19.1 (a) Write a mechanism. for...Ch. 19 - Practice Problem 19.2
Since the products obtained...Ch. 19 - Prob. 3PPCh. 19 - PRACTICE PROBLEM 19.4
Write mechanisms that...Ch. 19 - Prob. 5PPCh. 19 - Prob. 6PPCh. 19 - Practice Problem 19.7 The acid-catalyzed aldol...Ch. 19 - Prob. 8PPCh. 19 - Practice Problem 19.9
(a) Provide a mechanism for...Ch. 19 - Prob. 10PP
Ch. 19 - Practice Problem 19.11 Outlined below is a...Ch. 19 - Prob. 12PPCh. 19 - Prob. 13PPCh. 19 - Prob. 14PPCh. 19 - Practice Problem 19.15
Starting with ketones and...Ch. 19 - Practice Problem 19.16 Assuming that dehydration...Ch. 19 - Practice Problem 19.17 What starting compound...Ch. 19 - Practice Problem 19.18
What experimental...Ch. 19 - Prob. 19PPCh. 19 - Practice Problem 19.20
When acrolein (propenal)...Ch. 19 - Prob. 21PPCh. 19 - PRACTICE PROBLEM 19.22
Qutline reasonable...Ch. 19 - Prob. 23PCh. 19 - Show all steps in the following syntheses. You may...Ch. 19 - Prob. 25PCh. 19 - Prob. 26PCh. 19 - Prob. 27PCh. 19 - 19.28 Show how the diketone at the right could be...Ch. 19 - Prob. 29PCh. 19 - 19.30 Write a detailed mechanism for the following...Ch. 19 - Prob. 31PCh. 19 - Prob. 32PCh. 19 - 19.33 Predict the products from each of the...Ch. 19 - Prob. 34PCh. 19 - Show how each of the following transformations...Ch. 19 - Prob. 36PCh. 19 - What reagents would you use to bring about each...Ch. 19 - Prob. 38PCh. 19 - Prob. 39PCh. 19 - 19.40 When the aldol reaction of acetaldehyde is...Ch. 19 - Prob. 41PCh. 19 - Prob. 42PCh. 19 - 19.43 The following reaction illustrates the...Ch. 19 - What is the structure of the cyclic compound that...Ch. 19 - Prob. 45PCh. 19 - Prob. 46PCh. 19 - Prob. 47PCh. 19 - Predict the products from the following reactions....Ch. 19 - Prob. 49PCh. 19 - Prob. 50PCh. 19 - Prob. 51PCh. 19 - Prob. 52PCh. 19 - Prob. 53PCh. 19 - The Perkin condensation is an aldol-type...Ch. 19 - 19.55 (a) Infrared spectroscopy provides an easy...Ch. 19 - Allowing acetone to react with 2 molar equivalents...Ch. 19 - (+) Fenchone is a terpenoid that can be isolated...Ch. 19 - Prob. 58PCh. 19 - Prob. 59PCh. 19 - 19.60 Develop a synthesis for the following...Ch. 19 - 19.61 Provide a mechanism for each of the...Ch. 19 - 19.62 (a) Deduce the structure of product A,...Ch. 19 - Prob. 63PCh. 19 - Prob. 1LGP
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- Show structures (in blank boxes) for the reactants/products in the following reactions.arrow_forwardbase 2 H3C H H3C OH heat H H3C + H₂O H The aldol reaction is a carbonyl condensation reaction between two carbonyl partners and involves a combination of nucleophilic addition and a-substitution steps. One partner is converted into an enolate ion nucleophile and adds to the electrophilic carbonyl group of the second partner. In the classic aldol reaction, the carbonyl partners are aldehydes or ketones, although aldehydes are more reactive. The product is a ẞ-hydroxy carbonyl compound. Under reaction conditions slightly more vigorous than those employed for the aldol reaction, the ẞ-hydroxyl group is eliminated in an E1CB dehydration to give an a,ẞ-unsaturated carbonyl compound. Draw curved arrows to show the movement of electrons in this step of the mechanism. Arrow-pushing Instructions X :OH H₂O: а کی H₂C H H₂C H Harrow_forwardA graduate student was studying enzymatic reductions of cyclohexanones when she encountered some interesting chemistry. When she used an enzyme and NADPH to reduce the following ketone, she was surprised to find that the product was optically active. She carefully repurified the product so that no enzyme, NADPH, or other contaminants were present. Still, the product was optically active. If this reaction could be accomplished using H2 and a nickel catalyst, would the product be optically active? Explain.arrow_forward
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- A graduate student was studying enzymatic reductions of cyclohexanones when she encountered some interesting chemistry. When she used an enzyme and NADPH to reduce the following ketone, she was surprised to find that the product was optically active. She carefully repurified the product so that no enzyme, NADPH, or other contaminants were present. Still, the product was optically active. Is the product capable of showing optical activity? If it is, explain how.arrow_forwardName the reaction HSO, 4 R- R=R .R R 1) R,BH R H R. 2) NaOH, HaO, O Hydration Acid-Catalyzed-Hydration O Hydrohalogenation Hydrogenation 工arrow_forwardbase H3C H OH heat H + H₂O H The aldol reaction is a carbonyl condensation reaction between two carbonyl partners and involves a combination of nucleophilic addition and a-substitution steps. One partner is converted into an enolate ion nucleophile and adds to the electrophilic carbonyl group of the second partner. In the classic aldol reaction, the carbonyl partners are aldehydes or ketones, although aldehydes are more reactive. The product is a ẞ-hydroxy carbonyl compound. In the mixed aldol reaction, the best results are obtained when one of the partners does not have an a-hydrogen. It cannot form an enolate anion and can therefore not undergo self-reaction. The enolizable aldehyde is added slowly to a basic solution of the first aldehyde so that the mixed product is preferentially formed. Under reaction conditions slightly more vigorous than those employed for the aldol reaction, the ẞ-hydroxyl group is eliminated in an E1cB dehydration to give an a,ß-unsaturated carbonyl compound.…arrow_forward
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