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- I keep getting 2 different answers can u please verify for me which is right? -1.69 or different onearrow_forwardThe equilibrium constant, K, for the following reaction is 2.01 at 500 K. PCl₂(g) + Cl₂(g) PCIg(8) If AH® for this reaction is -87.9 kj, what is the value of K₂ at 387 K? Kp Submit Answer Retry Endre Group No more group attempts remain hp Ⓡarrow_forwardConsider the reaction 2H202(1)2H20(1) + 02(g) Using the standard thermodynamic data in the tables linked above, calculate the equilibrium constant for this reaction at 298.15K. ANSWER: Submit Answer Retry Entire Group 9 more group attempts remainingarrow_forward
- Calculate K for the following reaction at 50 oC: 2 Li(s) + Ba2+(aq) ---> 2 Li+ + Ba(s) (need to calculate Ecell)arrow_forwardThe chemical reaction Fe[SCN]2⇋ Fe+2 +2SCN- a)is it endothermic or exothermic? b)What would happen if SCN- was decreased? c)What would happen if Fe+2 was increased?arrow_forwardGiven: P4(s)+5O2(g)⟶P4O10(s) ΔG°=−2697.0 kJ/mol 2H2(g)+O2(g)⟶2H2O(g) ΔG°=−457.18 kJ/mol 6H2O(g)+P4O10(s)⟶4H3PO4(l) ΔG°=−428.66 kJ/mol Net Equation: 3/2 H2 (g) + ¼ P4 (s) + 2 O2 (g) → H3PO4 (l) Using Hess’s law to determine the standard free energy of formation, ΔG∘f, for phosphoric acid.arrow_forward
- Calculate ∆Gº for the following reaction at 25ºC: Pb2+ + Fe --> Pb + Fe2+ -->arrow_forwardConsider the following two reductions: Pb+2 + 2e‾→Pb E°red = -0.13 V Sn+2 + 2e‾ → Sn E°red = -0.14 V Calculate the equilibrium constant at 25 0C? (A)1.3 x 109 (B)912 (c)2.2 (D)9.1arrow_forwardPROBLEM SOLVING NUMBER 3arrow_forward
- Using the thermodynamic data provided below, calculate K for Mg(OH) sp 26 s) at 25°.arrow_forwardsee photo. Problem # 15.18arrow_forwardGiven the following information: F1- (aq): ΔGf° = -276.48 kJ/mol Na1+ (aq): ΔGf° = -261.87 kJ/mol 2 Na (s) + F2 (g) → 2 NaF (aq) a) Find ΔG° for this reaction using the above numbers. b) Write the expression for Qeq. (Note that NaF is a strong electrolyte!) c) Find ΔG at 325.0 K for 0.01500 atm F2 and 3.065 M NaF.arrow_forward
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