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- Calculate ΔS°298 for the following changes.(a) SnCl4(l) ⟶ SnCl4(g)(b) CS2(g) ⟶ CS2(l)(c) Cu(s) ⟶ Cu(g)(d) H2 O(l) ⟶ H2 O(g)(e) 2H2(g) + O2(g) ⟶ 2H2 O(l)(f) 2HCl(g) + Pb(s) ⟶ PbCl2(s) + H2(g)(g) Zn(s) + CuSO4(s) ⟶ Cu(s) + ZnSO4(s)arrow_forwardWhich of the following is true for a particular reaction if AG° is -40.0 kJ/mol at 290 K and -20.0 kJ/mol at 390 K? A) ΔΗ >0 , ΔS 0 Β) ΔΗ 0, AS< 0 D) ΔΗ < 0, ΔS 0 E) None of these +arrow_forwardCalculate Kp for the following equation with a ΔGo for C2H4O = -13.1 kJ/mole at 25.0 oC. 2C2H4(g) + O2(g) →2C2H4O(g) Group of answer choices 2.68x10-29 5.17x10-15 2.48x1035 3.74x1028arrow_forward
- The Ksp for a very insoluble salt is 4.2 x 10-47 at 298 K. Whatis ΔG° for the dissolution of the salt in water?(a) -265 kJ/mol (b) -115 kJ/mol (c) -2.61 kJ/mol(d) +115 kJ/mol (e) +265 kJ/molarrow_forwardQUESTION 22 At what temperature, in Kelvin, does the following reaction change from spontaneous to non-spontaneous 2 A (aq) + 2 B (aq) 2 C (aq) + 1 D (aq) if AH° (A)= 0.8219 kJ/mol, AH° (B) = -40.5308 kJ/mol, AH° (C) = -85.3178 kJ/mol, and AH (D) = -70 8643 kJ/mol AS (A)= 76.117 J/(mol K), AS (B) = -15.8072 J/(mol K), AS (C) = 18.4425 J/(mol K), and AS" (D) = -8.6387 J/(mol K)arrow_forwardThe ΔG°rxn for this reaction is -107.8 kJ/mol. Given the values for ΔGf°; what is the ΔGf° for A2B(l)? 2AC(g) + B2(g) → A2B(l) + BC2(g) Substance ΔGf° (kJ/mol) AC(g) -174.3 B2(g) 173.3 BC2(g) 169.9arrow_forward
- What happens to ΔG°298 (becomes more negative or more positive) for the following chemical reactions when the partial pressure of oxygen is increased?(a) S(s) + O2(g) ⟶ SO2(g)(b) 2SO2(g) + O2(g) ⟶ SO3(g)(c) HgO(s) ⟶ Hg(l) + O2(g)arrow_forwardPlease correct answer and don't use hand ratingarrow_forward2) a)Determine AGX"° values for the following Combustion reactions at 25°C b) Decide whether this reaction is spontanious at 25°C or not CH:(g) + 02(g) CO:(g) + H;0 (1) AH (kJ/mol) s° (kJ/mol) CH4 -74.87 0.186 0.205 CO2 H,O -393.51 0.214 -285.83 0.070arrow_forward
- Calculate the equilibrium constant at 25 °C for each of the following reactions from the value of ΔG° given.(a) I2(s) + Cl2(g) ⟶ 2ICl(g) ΔG° = −10.88 kJ(b) H2(g) + I2(s) ⟶ 2HI(g) ΔG° = 3.4 kJ(c) CS2(g) + 3Cl2(g) ⟶ CCl4(g) + S2 Cl2(g) ΔG° = −39 kJ(d) 2SO2(g) + O2(g) ⟶ 2SO3(g) ΔG° = −141.82 kJ(e) CS2(g) ⟶ CS2(l) ΔG° = −1.88 kJarrow_forwardGiven the following data, what is the value of ΔGf° (CH3OH(ℓ) at 25°C?CO(g) + 2 H2(g) ⇄ CH3OH(ℓ) K = 1.081 × 10-40ΔGf°(CO) = -137.2 kJ/molarrow_forwardCalculate T (in K) given ΔG^0= -19.4 kJ/mol and ΔH^0= 69.9 kJ/mol and ΔS^0= 253 J/mol KΔG^0=ΔH^0−TΔS^0 A) 706 B) 1,760 C) 353 D) 0.353 E) 118arrow_forward
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