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- Calculate ΔE, if q= 0.765 kJ and w= -850 Jarrow_forwardUsing the standard molar entropies in Appendix C, calculatethe standard entropy change, ΔS°, for the “water-splitting”reaction at 298 K:2 H2O(l)---->2 H2(g) + O2(g) (a) 326.3 J/K (b) 265.7 J/K (c) 163.2 J/K (d) 88.5 J/K(e) -326.3 J/Karrow_forward1. Consider the freezing of liquid water at -10°C and 1 atm. For this process, what are the signs for AH, AS, and AG? ΔΗ AS AG (A) (B) (C) (D) I + + 1 + 1 + 1arrow_forward
- 8arrow_forwardOne of the reactions that destroys ozone in the upper atmosphere is NO(g) + O3(g) ⇒ NO2 (g) + O2(g) Substance and State AGf (kJ/mol) NO(g) 87 NO₂(g) 52 0₂ (9) 0 03 (9) 163 a Calculate ΔG° (at 298 K) for this reaction. AG = -198 kJ b Calculate K (at 298 K) for this reaction. K =arrow_forwardc) SO d) CO 0. Sodium reacts violently with water according to the equation: 2 Na(s) +2 H;0() 2 NaOH(aq) + H:(g) resulting solution has a higher temperature than the water prior to the addition of sodium. What are the signs of AH and AS for this reaction? a) AH is negative and AS is negative. b) AH is negative and AS is positive. e) AH is positive and AS is negative. d) AH is positive and AS is positive. (END)arrow_forward
- 10:59 1 Question 13 of 20 Submit Which of the following sets of conditions is true for an exothermic reaction that is spontaneous at all temperatures? A) AH 0, AS 0 D) AH > 0, AS 0, ΔG <0arrow_forwardQuestion 4 4.1 When 0.50 mol of an ideal gas is expanded isothermally and reversibly at 298 K from a volume of 10.0 L to 25.0 L, (a) What is the 4Sgas? (b) How much work was done? (c) What is the 4Ssurr? (d) What is the 4Stotal? 4.2 At 25.0 °C the equilibrium constant for the reaction: CO(g) + H₂O(g) = CO2(g) + H2(g) is 1.00 x 10-5, and AS° is 41.8 J K-1 mol-¹. Calculate 4Gº and AH° at 25.0 °C.arrow_forwardThe equilibrium constant for a reaction is 0.48 at 25 °C. What is the value of ΔG° (kJ/mol) at this temperature?arrow_forward
- Given: P4(s)+5O2(g)⟶P4O10(s) ΔG°=−2697.0 kJ/mol 2H2(g)+O2(g)⟶2H2O(g) ΔG°=−457.18 kJ/mol 6H2O(g)+P4O10(s)⟶4H3PO4(l) ΔG°=−428.66 kJ/mol Net Equation: 3/2 H2 (g) + ¼ P4 (s) + 2 O2 (g) → H3PO4 (l) Using Hess’s law to determine the standard free energy of formation, ΔG∘f, for phosphoric acid.arrow_forwardQuestion attachedarrow_forwardWhat is ΔH° for the reaction below? TiCl4(g) + 2H2O(l) --> TiO2(s) + 4HCl(g)arrow_forward
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