Stokes’ Theorem for evaluating surface integrals Evaluate the line integral in stokes’ Theorem to determine the value of the surface integral ∬ s ( ∇ × F ) ∙ n dS . Assume n points in an upward direction. 24. F = 〈 e x , 1 / z , y 〉 ; S is the part of the surface z = 4 − 3 y 2 that lies within the paraboloid z = x 2 + y 2 .
Stokes’ Theorem for evaluating surface integrals Evaluate the line integral in stokes’ Theorem to determine the value of the surface integral ∬ s ( ∇ × F ) ∙ n dS . Assume n points in an upward direction. 24. F = 〈 e x , 1 / z , y 〉 ; S is the part of the surface z = 4 − 3 y 2 that lies within the paraboloid z = x 2 + y 2 .
Solution Summary: The author evaluates the surface integral by obtaining line integral in Stokes' theorem, where n is the unit vector normal to S determined by its orientation.
Stokes’ Theorem for evaluating surface integrals Evaluate the line integral in stokes’ Theorem to determine the value of the surface integral
∬
s
(
∇
×
F
)
∙ndS. Assume n points in an upward direction.
24.
F
=
〈
e
x
,
1
/
z
,
y
〉
; S is the part of the surface z = 4 − 3y2 that lies within the paraboloid z = x2 + y2.
With differentiation, one of the major concepts of calculus. Integration involves the calculation of an integral, which is useful to find many quantities such as areas, volumes, and displacement.
Stokes’ Theorem for evaluating surface integrals Evaluate the line integral in Stokes’ Theorem to determine the value of the surface integral ∫∫S (∇ x F) ⋅ n dS. Assume n points in an upward direction.
F = ⟨4x, -8z, 4y⟩; S is the part of the paraboloidz = 1 - 2x2 - 3y2 that lies within the paraboloid z = 2x2 + y2 .
Verify Stokes' theorem. Assume that the surface S is oriented upward. F=3zi−5xj+2yk; S that portion of the paraboloid z=36−x^2−y^2 for z≥0 I'm having trouble finding the normal n*dS in Stokes's Theorem
What is a unit normal to the surface x?y + 2xz = 4 at the point (2, –2, 3)
O+3+歌
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