Chapter 1.7, Problem 42CCR

To determine

The solution of the expression $5a-\left(b+c\right)$ ,

Answer to Problem 42CCR

  $5$

Explanation of Solution

Given:

The expression, $5a-\left(b+c\right)$ .If $a=3,b=8\text{and}c=2$

Concept Used:

• To get rid of a number in addition from one side, subtract the same number from both sides of equal sign.
• To get rid of a number in subtraction from one side, add the same number both sides of equal sign.
• To get rid of a number in multiplication from one side, divide the same number from both sides of equal sign.
• To get rid of a number in division from one side, multiply the same number both sides of equal sign.

Rules of Addition/ Subtraction:

• Two numbers with similar sign always get added and the resulting number will carry the similar sign.
• Two numbers with opposite signs always get subtracted and the resulting number will carry the sign of larger number.

Rules of Multiplication/ Division:

• The product/quotient of two similar sign numbers is always positive.
• The product/quotient of two numbers with opposite signs is always negative.

Calculation:

In order to solve the given expression $5a-\left(b+c\right)$ put the values $a=3,b=8\text{and}c=2$ in the given expression and then simplify further as shown below,

  $\begin{array}{c}5a-\left(b+c\right)\\ =5\cdot 3-\left(8+2\right)\\ =15-10\\ =5\end{array}$

Thus, the solution of the expression is $5$ .