Chapter 1.1, Problem 18CCR

To determine

Find the area of the figure given.

Answer to Problem 18CCR

  $20{\text{m}}^2$

Explanation of Solution

GIVEN:

  

Concept Used:

Area of triangle is $\text{A=}\frac{1}{2}bh$

b is base of the triangle and h is the height of the triangle.

In order to find the whole area of the figure, find the area of two triangles that make up the figure and adding the areas, first to find the area of left triangle using the formula of a triangle, that is $\text{A=}\frac{1}{2}bh$ , now putting the value of b , that is 4 and h , that is 4given in the question and then to find the area of right triangle using the formula of a triangle, that is $\text{A=}\frac{1}{2}bh$ , now putting the value of b , that is 6 and h , that is 4given in the question as shown below:

  $\begin{array}{l}\text{left triangle}\\ \text{A=}\frac{1}{2}bh\\ \text{A}=\frac{1}{2}\times 4\times 4\\ \text{A}=2\times 4\\ \text{A}=8{\text{m}}^2\end{array}$

  $\begin{array}{l}\text{right triangle}\\ \text{A=}\frac{1}{2}bh\\ \text{A}=\frac{1}{2}\times 6\times 4\\ \text{A}=3\times 4\\ \text{A}=12{\text{m}}^2\end{array}$

Now, adding both the area of tirangle :

  $\begin{array}{l}\text{left triangle +right triangle}\\ ={\text{8m}}^2+12{\text{m}}^2\\ =20{\text{m}}^2\end{array}$

So, the area of the figure is ${\text{20m}}^2$