Chapter 1.2, Problem 11GP

To determine

Write and evaluate an expression to find the cost of 25 passengers. And then make a table showing the cost for 25, 30, 35, and 40 passengers.

Answer to Problem 11GP

  $\begin{array}{l}\text{Expression: }75+6\times \text{passengers}\\ \$225\text{for 25 passengers}\end{array}$

PASSENGERS	COST
1	$\begin{array}{l}75+6\times \text{passengers}=75+6\times 1\\ =\$81\end{array}$
25	$\begin{array}{l}75+6\times \text{passengers}=75+6\times 25\\ =\$225\end{array}$
30	$\begin{array}{l}75+6\times \text{passengers}=75+6\times 30\\ =\$255\end{array}$
35	$\begin{array}{l}75+6\times \text{passengers}=75+6\times 35\\ =\$285\end{array}$
40	$\begin{array}{l}75+6\times \text{passengers}=75+6\times 40\\ =\$315\end{array}$

Explanation of Solution

GIVEN:

A tour bus cost $7 plus $6 for each passenger.

In order to write and evaluate an expression to find the cost of 25 passengers, first the cost is 75 added to 6 times the number of passengers, so the expression is as shown below:

  $75+6\times \text{passengers}$

Now, putting the number of passengers, that is 25 in the above expression and solving it as shown below:

  $\begin{array}{l}75+6\times \text{passengers}\\ =\text{75+6}\times \text{25}\\ \text{=75+150}\\ \text{=\$225}\end{array}$

So, the cost of 25 passengers is $225.

Now, in order to make a table showing the cost for 25, 30, 35, and 40 passengers are:

PASSENGERS	COST
1	$\begin{array}{l}75+6\times \text{passengers}=75+6\times 1\\ =\$81\end{array}$
25	$\begin{array}{l}75+6\times \text{passengers}=75+6\times 25\\ =\$225\end{array}$
30	$\begin{array}{l}75+6\times \text{passengers}=75+6\times 30\\ =\$255\end{array}$
35	$\begin{array}{l}75+6\times \text{passengers}=75+6\times 35\\ =\$285\end{array}$
40	$\begin{array}{l}75+6\times \text{passengers}=75+6\times 40\\ =\$315\end{array}$