Chapter 1.7, Problem 1GP

To determine

The domain and range of the relation.

Answer to Problem 1GP

The final table is

Number of Touchdowns	Number of Points
X	Y
1	6
2	12
5	30
7	42

Explanation of Solution

Given:

The team score 6 points for each touchdown $\begin{array}{l}y=\text{6(number of touchdowns)}\\ y=6\cdot x\end{array}$

  

Concept Used:

• To get rid of a number in addition from one side, subtract the same number from both sides of equal sign.
• To get rid of a number in subtraction from one side, add the same number both sides of equal sign.
• To get rid of a number in multiplication from one side, divide the same number from both sides of equal sign.
• To get rid of a number in division from one side, multiply the same number both sides of equal sign.

Rules of Addition/ Subtraction:

• Two numbers with similar sign always get added and the resulting number will carry the similar sign.
• Two numbers with opposite signs always get subtracted and the resulting number will carry the sign of larger number.

Rules of Multiplication/ Division:

• The product/quotient of two similar sign numbers is always positive.
• The product/quotient of two numbers with opposite signs is always negative.

Calculation:

In order to solve the given table. Here to solve the table and simplify as shown below,

  $\begin{array}{c}y=6\cdot x\\ x=1\\ \text{Then}y=6\cdot 1\\ =6\\ x=2\\ \text{Then}y=6\cdot 2\\ =12\\ x=3\\ \text{Then}y=6\cdot 3\\ =18\\ x=5\\ \text{Then}y=6\cdot 5\\ =30\\ x=7\\ \text{Then}y=6\cdot 7\\ =42\end{array}$

Thus, the final table is below.

Number of Touchdowns	Number of Points
X	Y
1	6
2	12
5	30
7	42