Chapter 1.2, Problem 32IP

(a)

To determine

Write an expression that can be used to find total cost of admission for 4 adults, 3 children and 1 senior.

Answer to Problem 32IP

  $\text{total cost}=4\left(\text{cost of 1 adult}\right)+3\left(\text{cost of 1children}\right)+1\left(\text{cost of 1 senior}\right)$

Explanation of Solution

GIVEN:

  

Calculation:

In order to write an expression that can be used to find the total cost of admission for 4 adults, 3 children and 1 senior, first multiplying 4 adults to cost of 1 adult given in the question, then multiplying 3 childrens to cost of 1 children and then multiplying 1 senior to cost of 1 senior then, adding 3 of them so, the expression is as shown below:

  $\text{total cost}=4\left(\text{cost of 1 adult}\right)+3\left(\text{cost of 1children}\right)+1\left(\text{cost of 1 senior}\right)$

(b)

To determine

Find the total cost .

Answer to Problem 32IP

  $\$51$

Explanation of Solution

GIVEN:

  

Calculation:

In order find the total cost, first putting the value of cost of 1 adult, that is $ 8 , the value of cost of 1 children, that is $5, and the value of 1 senior, that is $4 in the expression $\text{total cost}=4\left(\text{cost of 1 adult}\right)+3\left(\text{cost of 1children}\right)+1\left(\text{cost of 1 senior}\right)$ and solving it as shown below:

  $\begin{array}{l}\text{total cost}=4\left(\text{cost of 1 adult}\right)+3\left(\text{cost of 1children}\right)+1\left(\text{cost of 1 senior}\right)\\ \text{total cost}=4\left(8\right)+3\left(5\right)+1\left(4\right)\\ \text{total cost}=32+15+4\\ \text{total cost}=51\end{array}$

So, the total cost is $51.