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Concept explainers
(a)
Interpretation:
In the given acid‑base equilibria, the structure of missing substance has to be shown.
Concept Introduction:
Substituted ammonium ion is the one in which one or more alkyl, aryl, or cycloalkyl groups are substituted instead of hydrogen atoms. There are two important generalizations that is applied to the substituted ammonium ion and they are,
- Substituted ammonium ions are not neutral molecules. They are charged species.
- Nitrogen atom has four bonds in ammonium ion or substituted ammonium ion. The species is positively charged as the fourth bond formed is a coordinate covalent bond.
(b)
Interpretation:
In the given acid‑base equilibria, the structure of missing substance has to be shown.
Concept Introduction:
Amines are a class of organic compounds. They are derivatives of ammonia. Similar to the nitrogen atom in ammonia, the amine nitrogen also has a lone pair of electrons on it. This means that amines can act as proton acceptors. When an amine is added to water a proton is transferred to the nitrogen atom. The resulting solution is a basic solution. This contains ammonium ions and hydroxide ions.
Substituted ammonium ion is the one in which one or more alkyl, aryl, or cycloalkyl groups are substituted instead of hydrogen atoms. There are two important generalizations that is applied to the substituted ammonium ion and they are,
- Substituted ammonium ions are not neutral molecules. They are charged species.
- Nitrogen atom has four bonds in ammonium ion or substituted ammonium ion. The species is positively charged as the fourth bond formed is a coordinate covalent bond.
(c)
Interpretation:
In the given acid‑base equilibria, the structure of missing substance has to be shown.
Concept Introduction:
Amines are a class of organic compounds. They are derivatives of ammonia. Similar to the nitrogen atom in ammonia, the amine nitrogen also has a lone pair of electrons on it. This means that amines can act as proton acceptors. When an amine is added to water a proton is transferred to the nitrogen atom. The resulting solution is a basic solution. This contains ammonium ions and hydroxide ions.
Substituted ammonium ion is the one in which one or more alkyl, aryl, or cycloalkyl groups are substituted instead of hydrogen atoms. There are two important generalizations that is applied to the substituted ammonium ion and they are,
- Substituted ammonium ions are not neutral molecules. They are charged species.
- Nitrogen atom has four bonds in ammonium ion or substituted ammonium ion. The species is positively charged as the fourth bond formed is a coordinate covalent bond.
(d)
Interpretation:
In the given acid‑base equilibria, the structure of missing substance has to be shown.
Concept Introduction:
Amines are a class of organic compounds. They are derivatives of ammonia. Similar to the nitrogen atom in ammonia, the amine nitrogen also has a lone pair of electrons on it. This means that amines can act as proton acceptors. When an amine is added to water a proton is transferred to the nitrogen atom. The resulting solution is a basic solution. This contains ammonium ions and hydroxide ions.
Substituted ammonium ion is the one in which one or more alkyl, aryl, or cycloalkyl groups are substituted instead of hydrogen atoms. There are two important generalizations that is applied to the substituted ammonium ion and they are,
- Substituted ammonium ions are not neutral molecules. They are charged species.
- Nitrogen atom has four bonds in ammonium ion or substituted ammonium ion. The species is positively charged as the fourth bond formed is a coordinate covalent bond.
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Chapter 17 Solutions
General, Organic, and Biological Chemistry
- Calsulate specific heat Dissolution of NaOH ก ง ง Mass of water in cup Final temp. of water + NaOH Initial temp. of water AT Water AH Dissolution NaOH - "CaicuraORT. AH (NaOH)=-AH( 30g (water) 29.0°C 210°C 8°C (82) 100 3.. =1003.20 Conjosarrow_forwardPlease provide throrough analysis to apply into further problems.arrow_forwardMolecular ion peak: the peak corresponding to the intact morecure (with a positive charge) 4. What would the base peak and Molecular ion peaks when isobutane is subjected to Mass spectrometry? Draw the structures and write the molecular weights of the fragments. 5. Circle most stable cation a) tert-butyl cation b) Isopropyl cation c) Ethyl cation. d)Methyl cationarrow_forward
- How many arrangements are there of 15 indistinguishable lattice gas particles distributed on: a.V = 15 sites b.V = 16 sites c.V = 20 sitesarrow_forwardFor which element is the 3d subshell higher in energy than that 4s subshell? Group of answer choices Zr Ca V Niarrow_forwardii) Molecular ion peak :the peak corresponding to the intact molecule (with a positive charge) What would the base peak and Molecular ion peaks when isobutane is subjected to Mass spectrometry? Draw the structures and write the molecular weights of the fragments. Circle most stable cation a) tert-butyl cation b) Isopropyl cation c) Ethyl cation. d) Methyl cation 6. What does a loss of 15 represent in Mass spectrum? a fragment of the molecule with a mass of 15 atomic mass units has been lost during the ionization Process 7. Write the isotopes and their % abundance of isotopes of i) Clarrow_forward
- Choose a number and match the atomic number to your element on the periodic table. For your element, write each of these features on a side of your figure. 1. Element Name and symbol 2. Family and group 3. What is it used for? 4. Sketch the Valence electron orbital 5. What ions formed. What is it's block on the periodic table. 6. Common compounds 7. Atomic number 8. Mass number 9. Number of neutrons- (show calculations) 10. Sketch the spectral display of the element 11.Properties 12. Electron configuration 13. Submit a video of a 3-meter toss in slow-moarrow_forward[In this question, there are multiple answers to type in a "fill-in-the-blank" fashion - in each case, type in a whole number.] Consider using Slater's Rules to calculate the shielding factor (S) for the last electron in silicon (Si). There will be electrons with a 0.35 S-multiplier, electrons with a 0.85 S-multiplier, and electrons with a 1.00 S-multiplier.arrow_forwardProvide the unknown for the given data.arrow_forward
- Draw the Lewis structures of two methanol (CH3OH) molecules and depict hydrogenbonding between them with dashed lines. Show all lone pairs. Provide a thorough analysis to apply concept idea into other problems.arrow_forwardSteps and explanation please.arrow_forwardHow could you distinguish between each pair of compounds below using IR? For each pair citeone bond and it’s frequency that you could use to distinguish between them. Please provide thorough analysis to apply into further problems.arrow_forward
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