Chemistry: Matter and Change
Chemistry: Matter and Change
1st Edition
ISBN: 9780078746376
Author: Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom
Publisher: Glencoe/McGraw-Hill School Pub Co
Question
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Chapter 15.2, Problem 19SSC
Interpretation Introduction

Interpretation:

The need for specific heat capacity in calculating the amount of heat absorbed or released by a substance when its temperature changes is to be highlighted.

Concept introduction:

The heat absorbed or released by a substance is dependent on three factors:

  1. The mass of the substance.
  2. The nature of the substance, its specific heat capacity.
  3. The change in temperature of the substance.

The unit of heat is Joules (J), specific heat capacity is J/(kg degree Celsius), and that of mass is kg.

Expert Solution & Answer
Check Mark

Answer to Problem 19SSC

The mathematical formula to calculate the heat absorbed or released by a substance when the temperature changes is,

Q=m×c×ΔT

Where,

Q is the heat released or absorbed,

m is the mass of the substance,

c is the specific heat of the substance,

ΔT is the difference between the initial and the final temperatures.

The specific heat capacity is a constant. By knowing the value of this fixed constant, the amount of heat produced or amount for an unknown mass of the substance can be directly calculated.

Explanation of Solution

Let say a 1kg of a substance melts by absorbing Q amount of heat and a temperature change of T.

Now, to determine how much heat would be required to melt 20kg of this substance, can only be determined by actually experimenting with it or by using the mathematical formula of heat capacity. In this formula, only variable is the temperature change, mass and specific heat capacity are fixed parameters. This way the amount of heat needed can be calculated easily.

Conclusion

The mathematical formula to calculate the heat absorbed or released by a substance when its temperature changes is,

Q=m×c×ΔT

The specific heat capacity is a property of the substance. It is a constant and can be directly used in the above formula to calculate heat absorbed or released by different masses of the substance.

Chapter 15 Solutions

Chemistry: Matter and Change

Ch. 15.1 - Prob. 11SSCCh. 15.2 - Prob. 12PPCh. 15.2 - Prob. 13PPCh. 15.2 - Prob. 14PPCh. 15.2 - Prob. 15PPCh. 15.2 - Prob. 16SSCCh. 15.2 - Prob. 17SSCCh. 15.2 - Prob. 18SSCCh. 15.2 - Prob. 19SSCCh. 15.2 - Prob. 20SSCCh. 15.2 - Prob. 21SSCCh. 15.2 - Prob. 22SSCCh. 15.3 - Prob. 23PPCh. 15.3 - Prob. 24PPCh. 15.3 - Prob. 25PPCh. 15.3 - Prob. 26SSCCh. 15.3 - Prob. 27SSCCh. 15.3 - Prob. 28SSCCh. 15.3 - Prob. 29SSCCh. 15.3 - Prob. 30SSCCh. 15.3 - Prob. 31SSCCh. 15.4 - Prob. 32PPCh. 15.4 - Prob. 33PPCh. 15.4 - Prob. 34PPCh. 15.4 - Prob. 35PPCh. 15.4 - Prob. 36PPCh. 15.4 - Prob. 37PPCh. 15.4 - Prob. 38SSCCh. 15.4 - Prob. 39SSCCh. 15.4 - Prob. 40SSCCh. 15.4 - Prob. 41SSCCh. 15.4 - Prob. 42SSCCh. 15.4 - Prob. 43SSCCh. 15.5 - Prob. 44PPCh. 15.5 - Prob. 45PPCh. 15.5 - Prob. 46PPCh. 15.5 - Prob. 47PPCh. 15.5 - Prob. 48SSCCh. 15.5 - Prob. 49SSCCh. 15.5 - Prob. 50SSCCh. 15.5 - Prob. 51SSCCh. 15.5 - Prob. 52SSCCh. 15 - Prob. 53ACh. 15 - Prob. 54ACh. 15 - Prob. 55ACh. 15 - Prob. 56ACh. 15 - Prob. 57ACh. 15 - Prob. 58ACh. 15 - Prob. 59ACh. 15 - Prob. 60ACh. 15 - Prob. 61ACh. 15 - Prob. 62ACh. 15 - Prob. 63ACh. 15 - Prob. 64ACh. 15 - Prob. 65ACh. 15 - Prob. 66ACh. 15 - Metallurgy A 25.0-g bolt made of an alloy...Ch. 15 - Prob. 68ACh. 15 - Prob. 69ACh. 15 - Prob. 70ACh. 15 - Prob. 71ACh. 15 - Prob. 72ACh. 15 - Prob. 73ACh. 15 - How many joules of heat are lost by 3580 kg of...Ch. 15 - Swimming Pool A swimming pool measuring 20.0m12.5m...Ch. 15 - How much heat is absorbed by a 44.7-g piece of...Ch. 15 - Prob. 77ACh. 15 - Alloys When a 58.8-g piece of hot alloy is placed...Ch. 15 - Prob. 79ACh. 15 - Prob. 80ACh. 15 - Prob. 81ACh. 15 - Prob. 82ACh. 15 - sUse information from Figure 15.24 to calculate...Ch. 15 - Agriculture Water is sprayed on oranges during...Ch. 15 - Grilling What mass of propane (C3H8) must be...Ch. 15 - Heating with Coal How much heat is liberated...Ch. 15 - How much heat is evolved when 1255 g of water...Ch. 15 - A sample of ammonia (Hsolid=5.66kJ/mol)...Ch. 15 - Prob. 89ACh. 15 - Prob. 90ACh. 15 - Prob. 91ACh. 15 - Prob. 92ACh. 15 - Prob. 93ACh. 15 - Prob. 94ACh. 15 - Prob. 95ACh. 15 - Prob. 96ACh. 15 - Prob. 97ACh. 15 - Prob. 98ACh. 15 - Prob. 99ACh. 15 - Prob. 100ACh. 15 - Prob. 101ACh. 15 - Prob. 102ACh. 15 - Prob. 103ACh. 15 - Heat was added consistently to a sample of water...Ch. 15 - Bicycling Describe the energy conversions that...Ch. 15 - Hiking Imagine that on a cold day you are planning...Ch. 15 - Differentiate between the enthalpy of formation of...Ch. 15 - Analyze both of the images in Figure 15.27 in...Ch. 15 - Apply Phosphorus trichloride is a starting...Ch. 15 - Calculate Suppose that two pieces of iron, one...Ch. 15 - Prob. 111ACh. 15 - sample of natural gas is analyzed and found to...Ch. 15 - Prob. 113ACh. 15 - Prob. 114ACh. 15 - Prob. 115ACh. 15 - Prob. 116ACh. 15 - Prob. 117ACh. 15 - Prob. 118ACh. 15 - Prob. 119ACh. 15 - Prob. 120ACh. 15 - Prob. 121ACh. 15 - Prob. 122ACh. 15 - Prob. 123ACh. 15 - Prob. 124ACh. 15 - Prob. 125ACh. 15 - Prob. 126ACh. 15 - Prob. 127ACh. 15 - Prob. 1STPCh. 15 - Prob. 2STPCh. 15 - Prob. 3STPCh. 15 - Prob. 4STPCh. 15 - Prob. 5STPCh. 15 - Prob. 6STPCh. 15 - Prob. 7STPCh. 15 - Prob. 8STPCh. 15 - Prob. 9STPCh. 15 - Prob. 10STPCh. 15 - Prob. 11STPCh. 15 - Prob. 12STPCh. 15 - Prob. 13STPCh. 15 - Prob. 14STPCh. 15 - Prob. 15STPCh. 15 - Prob. 16STPCh. 15 - Prob. 17STPCh. 15 - Prob. 18STP
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