Chemistry: Matter and Change
1st Edition
ISBN: 9780078746376
Author: Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom
Publisher: Glencoe/McGraw-Hill School Pub Co
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 15, Problem 115A
Interpretation Introduction
Interpretation:
The element from the electronic configuration needs to be identified.
Concept introduction:
Every atom has a unique electronic configuration decided by its number of electrons.
Expert Solution & Answer

Answer to Problem 115A
The element having given electronic configuration is copper.
Explanation of Solution
The given electronic configuration [Ar]4s13d5 suggests that the number of electrons are 18+1+5=24 which are the number of electrons present in copper.
Conclusion
Copper has the electronic configuration [Ar]4s13d5.
Chapter 15 Solutions
Chemistry: Matter and Change
Ch. 15.1 - Prob. 1PPCh. 15.1 - Prob. 2PPCh. 15.1 - Prob. 3PPCh. 15.1 - Prob. 4PPCh. 15.1 - Prob. 5PPCh. 15.1 - Prob. 6PPCh. 15.1 - Prob. 7SSCCh. 15.1 - Prob. 8SSCCh. 15.1 - Prob. 9SSCCh. 15.1 - Prob. 10SSC
Ch. 15.1 - Prob. 11SSCCh. 15.2 - Prob. 12PPCh. 15.2 - Prob. 13PPCh. 15.2 - Prob. 14PPCh. 15.2 - Prob. 15PPCh. 15.2 - Prob. 16SSCCh. 15.2 - Prob. 17SSCCh. 15.2 - Prob. 18SSCCh. 15.2 - Prob. 19SSCCh. 15.2 - Prob. 20SSCCh. 15.2 - Prob. 21SSCCh. 15.2 - Prob. 22SSCCh. 15.3 - Prob. 23PPCh. 15.3 - Prob. 24PPCh. 15.3 - Prob. 25PPCh. 15.3 - Prob. 26SSCCh. 15.3 - Prob. 27SSCCh. 15.3 - Prob. 28SSCCh. 15.3 - Prob. 29SSCCh. 15.3 - Prob. 30SSCCh. 15.3 - Prob. 31SSCCh. 15.4 - Prob. 32PPCh. 15.4 - Prob. 33PPCh. 15.4 - Prob. 34PPCh. 15.4 - Prob. 35PPCh. 15.4 - Prob. 36PPCh. 15.4 - Prob. 37PPCh. 15.4 - Prob. 38SSCCh. 15.4 - Prob. 39SSCCh. 15.4 - Prob. 40SSCCh. 15.4 - Prob. 41SSCCh. 15.4 - Prob. 42SSCCh. 15.4 - Prob. 43SSCCh. 15.5 - Prob. 44PPCh. 15.5 - Prob. 45PPCh. 15.5 - Prob. 46PPCh. 15.5 - Prob. 47PPCh. 15.5 - Prob. 48SSCCh. 15.5 - Prob. 49SSCCh. 15.5 - Prob. 50SSCCh. 15.5 - Prob. 51SSCCh. 15.5 - Prob. 52SSCCh. 15 - Prob. 53ACh. 15 - Prob. 54ACh. 15 - Prob. 55ACh. 15 - Prob. 56ACh. 15 - Prob. 57ACh. 15 - Prob. 58ACh. 15 - Prob. 59ACh. 15 - Prob. 60ACh. 15 - Prob. 61ACh. 15 - Prob. 62ACh. 15 - Prob. 63ACh. 15 - Prob. 64ACh. 15 - Prob. 65ACh. 15 - Prob. 66ACh. 15 - Metallurgy A 25.0-g bolt made of an alloy...Ch. 15 - Prob. 68ACh. 15 - Prob. 69ACh. 15 - Prob. 70ACh. 15 - Prob. 71ACh. 15 - Prob. 72ACh. 15 - Prob. 73ACh. 15 - How many joules of heat are lost by 3580 kg of...Ch. 15 - Swimming Pool A swimming pool measuring 20.0m12.5m...Ch. 15 - How much heat is absorbed by a 44.7-g piece of...Ch. 15 - Prob. 77ACh. 15 - Alloys When a 58.8-g piece of hot alloy is placed...Ch. 15 - Prob. 79ACh. 15 - Prob. 80ACh. 15 - Prob. 81ACh. 15 - Prob. 82ACh. 15 - sUse information from Figure 15.24 to calculate...Ch. 15 - Agriculture Water is sprayed on oranges during...Ch. 15 - Grilling What mass of propane (C3H8) must be...Ch. 15 - Heating with Coal How much heat is liberated...Ch. 15 - How much heat is evolved when 1255 g of water...Ch. 15 - A sample of ammonia (Hsolid=5.66kJ/mol)...Ch. 15 - Prob. 89ACh. 15 - Prob. 90ACh. 15 - Prob. 91ACh. 15 - Prob. 92ACh. 15 - Prob. 93ACh. 15 - Prob. 94ACh. 15 - Prob. 95ACh. 15 - Prob. 96ACh. 15 - Prob. 97ACh. 15 - Prob. 98ACh. 15 - Prob. 99ACh. 15 - Prob. 100ACh. 15 - Prob. 101ACh. 15 - Prob. 102ACh. 15 - Prob. 103ACh. 15 - Heat was added consistently to a sample of water...Ch. 15 - Bicycling Describe the energy conversions that...Ch. 15 - Hiking Imagine that on a cold day you are planning...Ch. 15 - Differentiate between the enthalpy of formation of...Ch. 15 - Analyze both of the images in Figure 15.27 in...Ch. 15 - Apply Phosphorus trichloride is a starting...Ch. 15 - Calculate Suppose that two pieces of iron, one...Ch. 15 - Prob. 111ACh. 15 - sample of natural gas is analyzed and found to...Ch. 15 - Prob. 113ACh. 15 - Prob. 114ACh. 15 - Prob. 115ACh. 15 - Prob. 116ACh. 15 - Prob. 117ACh. 15 - Prob. 118ACh. 15 - Prob. 119ACh. 15 - Prob. 120ACh. 15 - Prob. 121ACh. 15 - Prob. 122ACh. 15 - Prob. 123ACh. 15 - Prob. 124ACh. 15 - Prob. 125ACh. 15 - Prob. 126ACh. 15 - Prob. 127ACh. 15 - Prob. 1STPCh. 15 - Prob. 2STPCh. 15 - Prob. 3STPCh. 15 - Prob. 4STPCh. 15 - Prob. 5STPCh. 15 - Prob. 6STPCh. 15 - Prob. 7STPCh. 15 - Prob. 8STPCh. 15 - Prob. 9STPCh. 15 - Prob. 10STPCh. 15 - Prob. 11STPCh. 15 - Prob. 12STPCh. 15 - Prob. 13STPCh. 15 - Prob. 14STPCh. 15 - Prob. 15STPCh. 15 - Prob. 16STPCh. 15 - Prob. 17STPCh. 15 - Prob. 18STP
Additional Science Textbook Solutions
Find more solutions based on key concepts
DRAW IT Pea plants heterozygous for flower position and stem length (AaTt) are allowed to self-pollinate, and ...
Campbell Biology (11th Edition)
Match the following examples of mutagens. Column A Column B ___a. A mutagen that is incorporated into DNA in pl...
Microbiology: An Introduction
4. Three groups of nonvascular plants are _______, ______, and _______. Three groups of seedless vascular plant...
Biology: Life on Earth (11th Edition)
1. A cyclist goes around a level, circular track at constant speed. Do you agree or disagree with the following...
College Physics: A Strategic Approach (3rd Edition)
1. Why is the quantum-mechanical model of the atom important for understanding chemistry?
Chemistry: Structure and Properties (2nd Edition)
18. SCIENTIFIC THINKING By measuring the fossil remains of Homo floresiensis, scientists have estimated its wei...
Campbell Biology: Concepts & Connections (9th Edition)
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Similar questions
- Indicate whether the product formed in the reaction exhibits tautomerism. If so, draw the structure of the tautomers. OC2H5 + CoHs-NH-NH,arrow_forwardExplain how substitutions at the 5-position of barbituric acid increase the compound's lipophilicity.arrow_forwardExplain how substitutions at the 5-position of phenobarbital increase the compound's lipophilicity.arrow_forward
- Name an interesting derivative of barbituric acid, describing its structure.arrow_forwardBriefly describe the synthesis mechanism of barbituric acid from the condensation of urea with a β-diketone.arrow_forwardGiven the hydrazones indicated, draw the structures of the enamines that can be formed. Indicate the most stable enamine (explain). C6H5 C6H5 H C6H5 Harrow_forward
- 4. Propose a Synthesis for the molecule below. You may use any starting materials containing 6 carbons or less (reagents that aren't incorporated into the final molecule such as PhзP do not count towards this total, and the starting material can have whatever non-carbon functional groups you want), and any of the reactions you have learned so far in organic chemistry I, II, and III. Your final answer should show each step separately, with intermediates and conditions clearly drawn.arrow_forwardIndicate the importance of the indole ring. Find a representative example and list 5 structures.arrow_forwardΌΗ 1) V2 CO 3 or Nalt In منهarrow_forward
- 6. The equilibrium constant for the reaction 2 HBr (g) → H2(g) + Br2(g) Can be expressed by the empirical formula 11790 K In K-6.375 + 0.6415 In(T K-¹) - T Use this formula to determine A,H as a function of temperature. Calculate A,-H at 25 °C and at 100 °C.arrow_forward3. Nitrosyl chloride, NOCI, decomposes according to 2 NOCI (g) → 2 NO(g) + Cl2(g) Assuming that we start with no moles of NOCl (g) and no NO(g) or Cl2(g), derive an expression for Kp in terms of the equilibrium value of the extent of reaction, Seq, and the pressure, P. Given that K₂ = 2.00 × 10-4, calculate Seq/ of 29/no when P = 0.080 bar. What is the new value по ƒª/ at equilibrium when P = 0.160 bar? Is this result in accord with Le Châtelier's Principle?arrow_forwardConsider the following chemical equilibrium: 2SO2(g) + O2(g) = 2SO3(g) • Write the equilibrium constant expression for this reaction. Now compare it to the equilibrium constant expression for the related reaction: • . 1 SO2(g) + O2(g) = SO3(g) 2 How do these two equilibrium expressions differ? What important principle about the dependence of equilibrium constants on the stoichiometry of a reaction can you learn from this comparison?arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill EducationPrinciples of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
- Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill EducationChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningElementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY

Chemistry
Chemistry
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Cengage Learning

Chemistry
Chemistry
ISBN:9781259911156
Author:Raymond Chang Dr., Jason Overby Professor
Publisher:McGraw-Hill Education

Principles of Instrumental Analysis
Chemistry
ISBN:9781305577213
Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:Cengage Learning

Organic Chemistry
Chemistry
ISBN:9780078021558
Author:Janice Gorzynski Smith Dr.
Publisher:McGraw-Hill Education

Chemistry: Principles and Reactions
Chemistry
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:Cengage Learning

Elementary Principles of Chemical Processes, Bind...
Chemistry
ISBN:9781118431221
Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:WILEY