Chapter 15, Problem 64A

Interpretation Introduction

Interpretation:

The Calories released in a process that involves combustion of 1 mol ethanol is to be calculated.

Concept introduction:

The given amount of energy is to be converted into Calories.

The conversion factor is:

$\begin{array}{l}1kJ=1000J\\ and1cal=4.184J\\ 1Cal=1000cal\end{array}$

Answer to Problem 64A

$1367kJ=327Calories$

Explanation of Solution

As, $\begin{array}{l}1kJ=1000J\\ and1cal=4.184J\\ 1Cal=1000cal\end{array}$

Therefore,

$\begin{array}{l}1367kJ=1367kJ\times \frac{1000J}{1kJ}\times \frac{1cal}{4.184J}\times \frac{1Calories}{1cal}\\ =327Calories\end{array}$