(a)
Interpretation:
The molecule that has higher boiling point among the given molecules has to be identified.
Concept Introduction:
Carbonyl groups are the one which contain a double bond between carbon and oxygen atom.
Aldehydes contain a carbonyl group that contains a hydrogen atom and a carbon atom bonded to it. Aldehyde that has one and two carbon atoms are gas at room temperature. The physical state of aldehyde that contains three carbon atoms to eleven carbon atoms that are not branched is liquid at room temperature. Aldehydes that contain more than eleven carbon atoms are solid at room temperature.
Ketones contain a carbonyl group that contains two carbon atoms bonded to it. For a compound to be ketone, a minimum of three carbon atom is required. Ketones that contain three carbon atoms to eight carbon atoms which have the carbonyl group at the second carbon atom are liquid at room temperature.
Boiling point is the temperature at which the liquid state gets converted into gaseous state. Aldehydes and ketones have their boiling points intermediate between the boiling points of alcohols and
(b)
Interpretation:
The molecule that has higher boiling point among the given molecules has to be identified.
Concept Introduction:
Carbonyl groups are the one which contain a double bond between carbon and oxygen atom. Aldehydes and ketones possess this carbonyl functional group in it. The structural representation of a carbonyl group can be given as shown below,
Aldehydes contain a carbonyl group that contains a hydrogen atom and a carbon atom bonded to it. Aldehyde that has one and two carbon atoms are gas at room temperature. The physical state of aldehyde that contains three carbon atoms to eleven carbon atoms that are not branched is liquid at room temperature. Aldehydes that contain more than eleven carbon atoms are solid at room temperature.
Ketones contain a carbonyl group that contains two carbon atoms bonded to it. For a compound to be ketone, a minimum of three carbon atom is required. Ketones that contain three carbon atoms to eight carbon atoms which have the carbonyl group at the second carbon atom are liquid at room temperature.
Boiling point is the temperature at which the liquid state gets converted into gaseous state. Aldehydes and ketones have their boiling points intermediate between the boiling points of alcohols and alkanes with similar molecular mass. Due to the dipole‑dipole interaction, aldehydes and ketones have higher boiling point than alkanes. Due to the absence of hydrogen bonding in aldehyde and ketones, they have lower boiling points than alcohols of similar molecular mass.
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Chapter 15 Solutions
EBK GENERAL, ORGANIC, AND BIOLOGICAL CH
- true or false The equilibrium constant for this reaction is 0.20. N2O4(g) ⇔ 2NO2(g) Based on the above, the equilibrium constant for the following reaction is 0.4. 2N2O4(g) ⇔ 4NO2(g)arrow_forwardtrue or false Using the following equilibrium, if heat is added the equilibrium will shift toward the reactants. N2(g) + 3H2(g) ⇔ 2NH3(g) + heatarrow_forwardTrue or False Using the following equilibrium, if heat is added the equilibrium will shift toward the products. N2O4(g) + heat ⇔ 2NO2(g)arrow_forward
- true or false Using the following equilibrium, if solid carbon is added the equilibrium will shift toward the products. C(s) + CO2(g) ⇔ 2CO(g)arrow_forwardProvide the complete mechanism for the reaction below. You must include appropriate arrows,intermediates, and formal charges. Please also provide a reason to explain why the 1,4-adduct is preferred over the 1,3-adduct.arrow_forwardWhich of the following pairs are resonance structures of one another? I. III. || III IV + II. :0: n P !༠ IV. EN: Narrow_forward
- Predict the major organic product(s) and byproducts (either organic or inorganic) for thefollowing reactions.arrow_forwardA 8.25 g sample of aluminum at 55°C released 2500 J of heat. The specific heat of aluminum is 0.900 J/g°C. The density of aluminum is 2.70 g/mL. Calculate the final temperature of the aluminum sample in °C.arrow_forwardPredict the major organic product(s) and byproducts (either organic or inorganic) for thefollowing reactions.arrow_forward
- Predict the major organic product(s) and byproducts (either organic or inorganic) for thefollowing reaction.arrow_forwardplease helparrow_forwardExperiment 1 Data Table 1: Conservation of Mass - Initial Mass Data Table 1 Data Table 2 Data Table 3 Data Table 4 Panel 1 Photo 1 Data Table 5 Reaction Mass of test tube and 5.0% HC₂H₂O2 (g) # (A) (B) Mass of NaHCO, (g) Mass of balloon and NaHCO, (g) (C) 0.10 1 0829 14.38g 0.20 2 0.929 14.29g 0.35 1.00g 3 14.25g 0.50 1.14g 14.29 Experiment 1 Data Table 2: Moles of HC2H3O2 Reaction Volume of Mass of Moles of HC₂H₂O₂ 5.0% Vinegar (g) (ML) 5.0 0.25 0042 mol 2 5.0 0.25 0042 mol 3 5.0 0.25 0042 mol 5.0 0.25 0042 mol Experiment 1 Data Table 3: Moles of NaHCO3 Reaction Mass of NaHCO (g) 10g 20g 35g 50g Experiment 1 Data Table 4: Theoretical Yield of CO₂ Reaction # 1 2 3 Experiment 1 Total mass before reaction (g) (D=A+C) 15.29 15.21g 15.25g 15.349 Exercise 1 Data Table 1 Data Table 2 Data Table 3 Data Table 4 Panel 1 Photo 1 Data Table 5 Exercise 1- Data Table 1 Data Table 2 DataTable 3 Data Table 4 Panel 1 Photo 1 Data Table 5 Exercise 1- Moles of NaHCO 0012 mol 0025 mol 0044 mol 0062 mol…arrow_forward
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