Organic Chemistry-Package(Custom)
Organic Chemistry-Package(Custom)
4th Edition
ISBN: 9781259141089
Author: SMITH
Publisher: MCG
bartleby

Concept explainers

Question
Book Icon
Chapter 15, Problem 15.2P
Interpretation Introduction

(a)

Interpretation:

The most stable radical that can result from cleavage of CH bond in the given molecule is to be drawn.

Concept introduction:

A free radical is an atom or ion with unpaired electrons. They are reactive intermediates formed by the homolysis of covalent bond. Free radicals are classified as 1°, 2° or 3° depending upon the number of alkyl groups attached to it. As number of alkyl substitutents increases, the stability of radical also increases. This is due to the fact alkyl substituents donate their electrons to electron deficient radicals.

Interpretation Introduction

(b)

Interpretation:

The most stable radical that can result from cleavage of CH bond in the given molecule is to be drawn.

Concept introduction:

A free radical is an atom or ion with unpaired electrons. They are reactive intermediates formed by the homolysis of covalent bond. Free radicals are classified as 1°, 2° or 3° depending upon the number of alkyl groups attached to it. The number of alkyl substitutents increases, the stability of radical increases. This is due to the fact alkyl substituents donate their electrons to electron deficient radicals.

Interpretation Introduction

(c)

Interpretation:

The most stable radical that can result from cleavage of CH bond in the given molecule is to be drawn.

Concept introduction:

A free radical is an atom or ion with unpaired electrons. They are reactive intermediates formed by the homolysis of covalent bond. Free radicals are classified as 1°, 2° or 3° depending upon the number of alkyl groups attached to it. The number of alkyl substitutents increases, the stability of radical increases. This is due to the fact alkyl substituents donate their electrons to electron deficient radicals.

Interpretation Introduction

(d)

Interpretation:

The most stable radical that can result from cleavage of CH bond in the given molecule is to be drawn.

Concept introduction:

A free radical is an atom or ion with unpaired electrons. They are reactive intermediates formed by the homolysis of covalent bond. Free radicals are classified as 1°, 2° or 3° depending upon the number of alkyl groups attached to it. The number of alkyl substitutents increases, the stability of radical increases. This is due to the fact alkyl substituents donate their electrons to electron deficient radicals.

Blurred answer
Students have asked these similar questions
3. Why did breaking the P-C single bond lead to the formation of 2 species containing a free radical (ie. where did those 2 electrons come from)? 4. Do you think the photoinitiator 2-hydroxy-2-methylpropiophenone would require a shorter or longer wavelength of light to create a free radical? Explain your answer using the table provided in question #2 (be specific). The structure of 2-hydroxy-2- methylpropiophenone is shown below. CH3 Figure 5: Structure of 2-hydroxy-2- methylpropiophenone. The wavy line shows OH the bond that is photo-sensitive (ie. the bond that will be broken by light). (Taken from Tehfe et al. 2013, http://www.mdpi.com/2076- 3417/3/2/490/htm) ČH3 5. Why is the PEGDA monomer soluble in water, but the polymer is not? In other words, why do you think forming a large molecule would lead to the formation of a solid? (Hint: think about the movement of molecules in a liquid vs solid phase). 6. Thinking about the octet rule, why do you think many free radicals are very…
The term free radical can be applied to: O any molecule or ion that doesn't conform to standards. any molecule or ion with an odd number of electrons. O any molecule or ion that is not bonded to anything else. O any molecule or ion that has a charged transition metal.
Which of the following statements about carbon radicals is not true?A) Carbon radicals are classified as primary, secondary, tertiary, or quaternary.B) A carbon radical is sp2 hybridized.C) The geometry of a carbon radical is trigonal planar.D) The unhybridized p orbital in a carbon radical contains the unpaired electron.

Chapter 15 Solutions

Organic Chemistry-Package(Custom)

Ch. 15 - Prob. 15.11PCh. 15 - Synthesize each compound from (CH3)3CH. a....Ch. 15 - Prob. 15.13PCh. 15 - Prob. 15.14PCh. 15 - Prob. 15.15PCh. 15 - Prob. 15.16PCh. 15 - Prob. 15.17PCh. 15 - Prob. 15.18PCh. 15 - Draw all constitutional isomers formed when each...Ch. 15 - Draw the structure of the four allylic halides...Ch. 15 - Which compounds can be prepared in good yield by...Ch. 15 - Which CH bond is most readily cleaved in linolenic...Ch. 15 - Prob. 15.23PCh. 15 - Draw the products formed when each alkene is...Ch. 15 - Problem 15.24 When adds to under radical...Ch. 15 - Prob. 15.26PCh. 15 - Draw an energy diagram for the two propagation...Ch. 15 - Prob. 15.28PCh. 15 - Problem 15.27 Draw the steps of the mechanism that...Ch. 15 - Prob. 15.30PCh. 15 - Prob. 15.31PCh. 15 - Prob. 15.32PCh. 15 - Prob. 15.33PCh. 15 - Why is a benzylic CH bond labeled in red unusually...Ch. 15 - Prob. 15.35PCh. 15 - Prob. 15.36PCh. 15 - Prob. 15.37PCh. 15 - Prob. 15.38PCh. 15 - What alkane is needed to make each alkyl halide by...Ch. 15 - Which alkyl halides can be prepared in good yield...Ch. 15 - Prob. 15.41PCh. 15 - 15.40 Explain why radical bromination of p-xylene...Ch. 15 - a. What product(s) (excluding stereoisomers) are...Ch. 15 - Prob. 15.44PCh. 15 - Prob. 15.45PCh. 15 - Prob. 15.46PCh. 15 - 15.44 Draw all constitutional isomers formed when...Ch. 15 - Draw the organic products formed in each reaction....Ch. 15 - Prob. 15.49PCh. 15 - 15.47 Treatment of a hydrocarbon A (molecular...Ch. 15 - Prob. 15.51PCh. 15 - Prob. 15.52PCh. 15 - Prob. 15.53PCh. 15 - Prob. 15.54PCh. 15 - 15.53 Consider the following bromination: . a....Ch. 15 - 15.54 Draw a stepwise mechanism for the following...Ch. 15 - Prob. 15.57PCh. 15 - An alternative mechanism for the propagation steps...Ch. 15 - Prob. 15.59PCh. 15 - Prob. 15.60PCh. 15 - Devise a synthesis of each compound from...Ch. 15 - Devise a synthesis of each target compound from...Ch. 15 - Devisea synthesis of each target compound from the...Ch. 15 - Devise a synthesis of each compound using CH3CH3...Ch. 15 - Prob. 15.65PCh. 15 - 15.63 As described in Section 9.16, the...Ch. 15 - 15.64 Ethers are oxidized with to form...Ch. 15 - Prob. 15.68PCh. 15 - Prob. 15.69PCh. 15 - 15.67 In cells, vitamin C exists largely as its...Ch. 15 - What monomer is needed to form each...Ch. 15 - Prob. 15.72PCh. 15 - Prob. 15.73PCh. 15 - 15.71 Draw a stepwise mechanism for the following...Ch. 15 - 15.72 As we will learn in Chapter 30, styrene...Ch. 15 - Prob. 15.76PCh. 15 - 15.74 A and B, isomers of molecular formula , are...Ch. 15 - Prob. 15.78PCh. 15 - Radical chlorination of CH3CH3 forms two minor...Ch. 15 - 15.76 Draw a stepwise mechanism for the...Ch. 15 - Prob. 15.81PCh. 15 - Prob. 15.82PCh. 15 - Prob. 15.83P
Knowledge Booster
Background pattern image
Chemistry
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
Text book image
EBK A SMALL SCALE APPROACH TO ORGANIC L
Chemistry
ISBN:9781305446021
Author:Lampman
Publisher:CENGAGE LEARNING - CONSIGNMENT
Text book image
Organic Chemistry: A Guided Inquiry
Chemistry
ISBN:9780618974122
Author:Andrei Straumanis
Publisher:Cengage Learning
Text book image
Organic Chemistry
Chemistry
ISBN:9781305580350
Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote
Publisher:Cengage Learning