Organic Chemistry-Package(Custom)
4th Edition
ISBN: 9781259141089
Author: SMITH
Publisher: MCG
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Chapter 15, Problem 15.16P
Interpretation Introduction
Interpretation: The propagation steps for the reaction of
Concept introduction: Ozone layer acts as a shield, which protects the earth surface from destructive ultraviolet radiations. Nitric oxide destroys ozone by radical chain mechanism.
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Deduce possible reactions steps (no photolysis) for Mechanism II following X + 03 → XO + O₂
step such that the sum of all mechanism steps does not destroy or create any ozone.
7. How fast is the oxidation of SO₂, in percent per
hour, in the gas phase for an OH concentration of
1 × 107 radicals cm-³, a typical peak concentration in
the lower troposphere? Comment on the significance of
your calculated rate in light of observed rates of SO₂
oxidation of up to 30% h-¹ in the troposphere.
Ozone formation in the troposphere involves the following steps:
(1) NO₂(e) → NO(g) + O(g)
(2)
0(e) + 0₂(g) → 0, (e)
The first step is initiated by the absorption of visible light. Calculate the longest wavelength required for step 1 at 25.0 "C. Round your answer to 4 significant
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Note: Reference the Fundamental constants and Thermodynamic properties of pure substances tables for additional Information.
λ=
nm
O
D
Chapter 15 Solutions
Organic Chemistry-Package(Custom)
Ch. 15 - Prob. 15.1PCh. 15 - Prob. 15.2PCh. 15 - Draw the product formed when a chlorine atom (Cl)...Ch. 15 - Prob. 15.4PCh. 15 - Prob. 15.5PCh. 15 - Problem 15.6 Using mechanism 15.1 as guide, write...Ch. 15 - Calculate m0 for the two propagation steps in the...Ch. 15 - Prob. 15.8PCh. 15 - Problem 15.8 Which bond in the each compound is...Ch. 15 - Prob. 15.10P
Ch. 15 - Prob. 15.11PCh. 15 - Synthesize each compound from (CH3)3CH. a....Ch. 15 - Prob. 15.13PCh. 15 - Prob. 15.14PCh. 15 - Prob. 15.15PCh. 15 - Prob. 15.16PCh. 15 - Prob. 15.17PCh. 15 - Prob. 15.18PCh. 15 - Draw all constitutional isomers formed when each...Ch. 15 - Draw the structure of the four allylic halides...Ch. 15 - Which compounds can be prepared in good yield by...Ch. 15 - Which CH bond is most readily cleaved in linolenic...Ch. 15 - Prob. 15.23PCh. 15 - Draw the products formed when each alkene is...Ch. 15 - Problem 15.24 When adds to under radical...Ch. 15 - Prob. 15.26PCh. 15 - Draw an energy diagram for the two propagation...Ch. 15 - Prob. 15.28PCh. 15 - Problem 15.27 Draw the steps of the mechanism that...Ch. 15 - Prob. 15.30PCh. 15 - Prob. 15.31PCh. 15 - Prob. 15.32PCh. 15 - Prob. 15.33PCh. 15 - Why is a benzylic CH bond labeled in red unusually...Ch. 15 - Prob. 15.35PCh. 15 - Prob. 15.36PCh. 15 - Prob. 15.37PCh. 15 - Prob. 15.38PCh. 15 - What alkane is needed to make each alkyl halide by...Ch. 15 - Which alkyl halides can be prepared in good yield...Ch. 15 - Prob. 15.41PCh. 15 - 15.40 Explain why radical bromination of p-xylene...Ch. 15 - a. What product(s) (excluding stereoisomers) are...Ch. 15 - Prob. 15.44PCh. 15 - Prob. 15.45PCh. 15 - Prob. 15.46PCh. 15 - 15.44 Draw all constitutional isomers formed when...Ch. 15 - Draw the organic products formed in each reaction....Ch. 15 - Prob. 15.49PCh. 15 - 15.47 Treatment of a hydrocarbon A (molecular...Ch. 15 - Prob. 15.51PCh. 15 - Prob. 15.52PCh. 15 - Prob. 15.53PCh. 15 - Prob. 15.54PCh. 15 - 15.53 Consider the following bromination: .
a....Ch. 15 - 15.54 Draw a stepwise mechanism for the following...Ch. 15 - Prob. 15.57PCh. 15 - An alternative mechanism for the propagation steps...Ch. 15 - Prob. 15.59PCh. 15 - Prob. 15.60PCh. 15 - Devise a synthesis of each compound from...Ch. 15 - Devise a synthesis of each target compound from...Ch. 15 - Devisea synthesis of each target compound from the...Ch. 15 - Devise a synthesis of each compound using CH3CH3...Ch. 15 - Prob. 15.65PCh. 15 - 15.63 As described in Section 9.16, the...Ch. 15 - 15.64 Ethers are oxidized with to form...Ch. 15 - Prob. 15.68PCh. 15 - Prob. 15.69PCh. 15 - 15.67 In cells, vitamin C exists largely as its...Ch. 15 - What monomer is needed to form each...Ch. 15 - Prob. 15.72PCh. 15 - Prob. 15.73PCh. 15 - 15.71 Draw a stepwise mechanism for the following...Ch. 15 - 15.72 As we will learn in Chapter 30, styrene...Ch. 15 - Prob. 15.76PCh. 15 - 15.74 A and B, isomers of molecular formula , are...Ch. 15 - Prob. 15.78PCh. 15 - Radical chlorination of CH3CH3 forms two minor...Ch. 15 - 15.76 Draw a stepwise mechanism for the...Ch. 15 - Prob. 15.81PCh. 15 - Prob. 15.82PCh. 15 - Prob. 15.83P
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- Is Mechanism I or Mechanism II of ozone destruction considered responsible for the ozone hole over the South Pole? O Mechanism II O Mechanism Iarrow_forwardSelect from the following which steps are involved in the natural production of ozone in the stratosphere. (You may select multiple if needed) O 3 02 (g) → 2 03 (g) + photon3 0;(g) –20:(g) + photon O O2 (g) + O (g) + M → O3 (g) + M+heato,g) + O(g) - M→ 0,(g) + M+heat 0 0 (g) + 0 (g)+0 (g) → O3 (g) + heatog) - 0(g)- Og) → 03(g) + heat D 02 (g) + photon → 2O (g)02(3) + photon →2013) O 02 (g) + 0 (g) + photon → O3 (g)0(g) -O)+ photonarrow_forwardOrganic molecules (that contain carbon and other elements) are often probed using IR radiation. Certain bonds within the molecules vibrate at certain frequencies. If the carbon-oxygen bond in a molecule absorbs radiation of wavelength 9.6 μm, what frequency is that radiation?arrow_forward
- The 1995 Nobel Prize in Chemistry was shared by Paul Crutzen, F. Sherwood Rowland, and Mario Molina for their work concerning the formation and decomposition of ozone in the stratosphere. Rowland and Molina hypothesized that chlorofluorocarbons (CFCS) in the stratosphere break down upon exposure to UV radiation, producing chlorine atoms. Chlorine was previously identified as a catalyst in the breakdown of ozone into oxygen gas. Using the enthalpy of reaction for two reactions with ozone, determine the enthalpy of reaction for the reaction of chlorine with ozone. (1) CIO(g) + 0,(g) → Cl(g) + 20,(g) AH;xn = –122.8 kJ (2) 20,(g) → 30,(g) 0,(g)+Cl(g) → CIO(g) + 0,(g) AHn = -285.3 kJ (3) AĦxn = ? AHixn = kJarrow_forwardThe 1995 Nobel Prize in Chemistry was shared by Paul Crutzen, F. Sherwood Rowland, and Mario Molina for their work concerning the formation and decomposition of ozone in the stratosphere. Rowland and Molina hypothesized that chlorofluorocarbons (CFCs) in the stratosphere break down upon exposure to UV radiation, producing chlorine atoms. Chlorine was previously identified as a catalyst in the breakdown of ozone into oxygen gas. Using the enthalpy of reaction for two reactions with ozone, determine the enthalpy of reaction for the reaction of chlorine with ozone. (1) C10(g) + O₂(g) → Cl(g) +20₂(g) AH (2) 20,(g) →30₂(g) (3) 0₂(g) + Cl(g) → CIO(g) + O₂(g) Allis= = -122.8 kJ AH = -285.3 kJ AHin = ? kJarrow_forwardThe 1995 Nobel Prize in Chemistry was shared by Paul Crutzen, F. Sherwood Rowland, and Mario Molina for their work concerning the formation and decomposition of ozone in the stratosphere. Rowland and Molina hypothesized that chlorofluorocarbons (CFCs) in the stratosphere break down upon exposure to UV radiation, producing chlorine atoms. Chlorine was previously identified as a catalyst in the breakdown of ozone into oxygen gas. Using the enthalpy of reaction for two reactions with ozone, determine the enthalpy of reaction for the reaction of chlorine with ozone. CIO(g) + O3(g) -> Cl(g) +202(g) AHxn = -122.8 kJ (1) (2) 203(g) - - 302(g) AHxn=-285.3 kJ (3) 03(g) + Cl(g) - CIO(g) + O2(g) AHixn= ? AHixn= kJarrow_forward
- The 1995 Nobel Prize in Chemistry was shared by Paul Crutzen, F. Sherwood Rowland, and Mario Molina for their work concerning the formation and decomposition of ozone in the stratosphere. Rowland and Molina hypothesized that chlorofluorocarbons (CFCs) in the stratosphere break down upon exposure to UV radiation, producing chlorine atoms. Chlorine was previously identified as a catalyst in the breakdown of ozone into oxygen gas. Using the enthalpy of reaction for two reactions with ozone, determine the enthalpy of reaction for the reaction of chlorine with ozone. (1)ClO(g)+O3(g)⟶Cl(g)+2O2(g)Δ?∘rxn=−122.8 kJ (2)2O3(g)⟶3O2(g)Δ?∘rxn=−285.3 kJ (3)O3(g)+Cl(g)⟶ClO(g)+O2(g) Δ?∘rxn= ?arrow_forwardThe 1995 Nobel Prize in Chemistry was shared by Paul Crutzen, F. Sherwood Rowland, and Mario Molina for their work concerning the formation and decomposition of ozone in the stratosphere. Rowland and Molina hypothesized that chlorofluorocarbons (CFCs) in the stratosphere break down upon exposure to UV radiation, producing chlorine atoms. Chlorine was previously identified as a catalyst in the breakdown of ozone into oxygen gas. Using the enthalpy of reaction for two reactions with ozone, determine the enthalpy of reaction for the reaction of chlorine with ozone. (1)ClO(g)+O3(g)⟶Cl(g)+2O2(g)Δ?∘rxn=−122.8 kJ(2)2O3(g)⟶3O2(g)Δ?∘rxn=−285.3 kJ(3)O3(g)+Cl(g)⟶ClO(g)+O2(g) Δ?∘rxn= ?(1)ClO(g)+O3(g)⟶Cl(g)+2O2(g)ΔHrxn°=−122.8 kJ(2)2O3(g)⟶3O2(g)ΔHrxn°=−285.3 kJ(3)O3(g)+Cl(g)⟶ClO(g)+O2(g) ΔHrxn°= ? Δ?∘rxn=ΔHrxn°=arrow_forwardThe 1995 Nobel Prize in Chemistry was shared by Paul Crutzen, F. Sherwood Rowland, and Mario Molina for their work concerning the formation and decomposition of ozone in the stratosphere. Rowland and Molina hypothesized that chlorofluorocarbons (CFCs) in the stratosphere break down upon exposure to UV radiation, producing chlorine atoms. Chlorine was previously identified as a catalyst in the breakdown of ozone into oxygen gas. Using the enthalpy of reaction for two reactions with ozone, determine the enthalpy of reaction for the reaction of chlorine with ozone. (1)ClO(g)+O3(g)⟶Cl(g)+2O2(g)ΔH∘rxn=−122.8 kJ(2)2O3(g)⟶3O2(g)ΔH∘rxn=−285.3 kJ(3)O3(g)+Cl(g)⟶ClO(g)+O2(g) ΔH∘rxn= ?(1)ClO(g)+O3(g)⟶Cl(g)+2O2(g)ΔHrxn°=−122.8 kJ(2)2O3(g)⟶3O2(g)ΔHrxn°=−285.3 kJ(3)O3(g)+Cl(g)⟶ClO(g)+O2(g) ΔHrxn°= ? ΔH∘rxn=ΔHrxn°=__________________________________________kJarrow_forward
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