Chlorine dioxide oxidizes iodide ion in aqueous solution to iodine; chlorine dioxide is reduced to chlorite ion. 2 ClO 2 ( a q ) + 2 I − ( a q ) → 2 ClO 2 − ( a q ) + I 2 ( a q ) The order of the reaction with respect to ClO 2 was determined by starting with a large excess of I − , so that its concentration was essentially constant. Then Rate = k [ ClO 2 ] m [ I − ] n = k ′ [ ClO 2 ] m where k ′ = k [I − ] n . Determine the order with respect to ClO 2 and the rate constant k ′ by plotting the following data assuming first- and then second-order kinetics. [Data from H. Fukutomi and G. Gordon, J. Am. Chem. Soc. , 89 , 1362 (1967).] Time (s) [ClO 2 ] (mol/L) 0.00 4.77 × 10 −4 1.00 4.31 × 10 −4 2.00 3.91 × 10 −4 3.00 3.53 × 10 −4 5.00 2.89 × 10 −4 10.00 1.76 × 10 −4 30.00 2.4 × 10 −5 50.00 3.2 × 10 −6
Chlorine dioxide oxidizes iodide ion in aqueous solution to iodine; chlorine dioxide is reduced to chlorite ion. 2 ClO 2 ( a q ) + 2 I − ( a q ) → 2 ClO 2 − ( a q ) + I 2 ( a q ) The order of the reaction with respect to ClO 2 was determined by starting with a large excess of I − , so that its concentration was essentially constant. Then Rate = k [ ClO 2 ] m [ I − ] n = k ′ [ ClO 2 ] m where k ′ = k [I − ] n . Determine the order with respect to ClO 2 and the rate constant k ′ by plotting the following data assuming first- and then second-order kinetics. [Data from H. Fukutomi and G. Gordon, J. Am. Chem. Soc. , 89 , 1362 (1967).] Time (s) [ClO 2 ] (mol/L) 0.00 4.77 × 10 −4 1.00 4.31 × 10 −4 2.00 3.91 × 10 −4 3.00 3.53 × 10 −4 5.00 2.89 × 10 −4 10.00 1.76 × 10 −4 30.00 2.4 × 10 −5 50.00 3.2 × 10 −6
Solution Summary: The author explains that the order of the reaction is first-order and the rate constant is 2.
Author: Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Chlorine dioxide oxidizes iodide ion in aqueous solution to iodine; chlorine dioxide is reduced to chlorite ion.
2
ClO
2
(
a
q
)
+
2
I
−
(
a
q
)
→
2
ClO
2
−
(
a
q
)
+
I
2
(
a
q
)
The order of the reaction with respect to ClO2 was determined by starting with a large excess of I−, so that its concentration was essentially constant. Then
Rate
=
k
[
ClO
2
]
m
[
I
−
]
n
=
k
′
[
ClO
2
]
m
where k′= k[I−]n. Determine the order with respect to ClO2 and the rate constant k′ by plotting the following data assuming first- and then second-order kinetics. [Data from H. Fukutomi and G. Gordon, J. Am. Chem. Soc., 89, 1362 (1967).]
There is an instrument in Johnson 334 that measures total-reflectance x-ray fluorescence (TXRF) to do elemental analysis (i.e., determine what elements are present in a sample). A researcher is preparing a to measure calcium content in a series of well water samples by TXRF with an internal standard of vanadium (atomic symbol: V). She has prepared a series of standard solutions to ensure a linear instrument response over the expected Ca concentration range of 40-80 ppm. The concentrations of Ca and V (ppm) and the instrument response (peak area, arbitrary units) are shown below. Also included is a sample spectrum. Equation 1 describes the response factor, K, relating the analyte signal (SA) and the standard signal (SIS) to their respective concentrations (CA and CIS).
Ca, ppm
V, ppm
SCa, arb. units
SV, arb. units
20.0
10.0
14375.11
14261.02
40.0
10.0
36182.15
17997.10
60.0
10.0
39275.74
12988.01
80.0
10.0
57530.75
14268.54
100.0…
A mixture of 0.568 M H₂O, 0.438 M Cl₂O, and 0.710 M HClO are enclosed in a vessel at 25 °C.
H₂O(g) + C₁₂O(g) = 2 HOCl(g)
K = 0.0900 at 25°C
с
Calculate the equilibrium concentrations of each gas at 25 °C.
[H₂O]=
[C₁₂O]=
[HOCI]=
M
Σ
M
What units (if any) does the response factor (K) have? Does the response factor (K) depend upon how the concentration is expressed (e.g. molarity, ppm, ppb, etc.)?
Chapter 13 Solutions
General Chemistry - Standalone book (MindTap Course List)
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