Dinitrogen pentoxide, N2O5, decomposes when heated in carbon tetrachloride solvent.N2O5 →2NO2 + 1/2 O2(g) If the rate constant for the decomposition of N2O5 is 6.2 x10-4/min, what is the half-life? (The rate law is first order in N2O5.)(a) How long would it take for the concentration of N2O5 to decrease to 25% of its initial value? (b) To 12.5% of its initial value?

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Dinitrogen pentoxide, N2O5, decomposes when heated in carbon tetrachloride solvent.N2O5 →2NO2 + 1/2 O2(g)

If the rate constant for the decomposition of N2O5 is 6.2 x10-4/min, what is the half-life? (The rate law is first order in N2O5.)(a) How long would it take for the concentration of N2O5 to decrease to 25% of its initial value? (b) To 12.5% of its initial value?

Expert Solution
Step 1 First order Kinetics

Given reaction is 

N2O5   →  2NO2 + 1/2 O2(g)

rate law 

rate α [N2O5]1 

rate =K [N2O5]1 

where 

K = rate constant = 6.2 x10-4/min

first order rate constant :

K = (2.303/t) log a /(a-x)

k = rate constant, t = time taken,

a = initial concentration of N2O=100 , x = percentage completed , (a-x) = remaining percentage

t1/2 and K relation :

t1/2 = 0.693/K

       = 0.693 / 6.2 x10-4 min-1  

       = 0.11177 x 10 min

       = 1117.7 min

 

 

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