Chapter 13, Problem 13.109CHP

(a)

Interpretation Introduction

Interpretation:

With the help of Arrhenius equation, it has to be explained that the rate of forward and reverse reaction increases by same factor.

Concept introduction:

Arrhenius equation:

$\text{k}\text{=}{\text{Ae}}^{\frac{{\text{-E}}_{\text{a}}}{\text{RT}}}$

Where,

k is rate constant.

T is absolute temperature (kelvin)

A is pre-exponential factor.

R is gas constant

${\text{E}}_{\text{a}}$ is activation energy

(b)

Interpretation Introduction

Interpretation:

With the help of equilibrium constant and rate constant of forward and reverse reaction, it has to be explained that the equilibrium constant does not vary by adding catalyst.

Concept introduction:

Arrhenius equation:

$\text{k}\text{=}{\text{Ae}}^{\frac{{\text{-E}}_{\text{a}}}{\text{RT}}}$

Where,

k is rate constant.

T is absolute temperature (kelvin)

A is pre-exponential factor.

R is gas constant

${\text{E}}_{\text{a}}$ is activation energy