6th Edition

ISBN: 9781319113339

Author: Starnes

Publisher: MAC HIGHER

Concept explainers

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Definition Definition Middle value of a data set. The median divides a data set into two halves, and it also called the 50th percentile. The median is much less affected by outliers and skewed data than the mean. If the number of elements in a dataset is odd, then the middlemost element of the data arranged in ascending or descending order is the median. If the number of elements in the dataset is even, the average of the two central elements of the arranged data is the median of the set. For example, if a dataset has five items—12, 13, 21, 27, 31—the median is the third item in ascending order, or 21. If a dataset has six items—12, 13, 21, 27, 31, 33—the median is the average of the third (21) and fourth (27) items. It is calculated as follows: (21 + 27) / 2 = 24.

Chapter 1.3, Problem 120E

(a)

To determine

To find: the distribution has a clear left-skewed shape.

(a)

Expert Solution

Answer to Problem 120E

Monday, Wednesday and Sunday

Explanation of Solution

Given:

PRACTICE OF STATISTICS F/AP EXAM, Chapter 1.3, Problem 120E , additional homework tip 1

The distribution has a skewed to the left shape, if the box of the box plot lies closest to the top between the whiskers of the box plot and if the horizontal line (median) in the box of the box plot lies near the top of the box.

It is observed that the distribution of Monday, Wednesday and Saturday have the left- skewed shape, because the box of the box plot is lying near the top between the whiskers of the box plot.

(b)

To determine

To find: the outlier stands out the most.

(b)

Expert Solution

Answer to Problem 120E

Outlier of the Friday distribution, the reason is that the outlier lies furthest from the box plot of the distribution

Explanation of Solution

Given:

PRACTICE OF STATISTICS F/AP EXAM, Chapter 1.3, Problem 120E , additional homework tip 2

The outliers are showed by little circles in the box plots.

It is observed that there are four distributions with outliers: Tuesday, Thursday, Friday and Sunday.

The outlier that stands out the most is the outlier that lies furthest from the box plot and therefore the outlier of Friday stands out the most, as it is furthest from the box plot.

(c)

To determine

To find: the typical amount of sleep that the students got compare on these 7 nights.

(c)

Expert Solution

Answer to Problem 120E

The highest typical amount of sleep occurs on Friday, while the lowest typical amount of sleep occurs on Thursday and the typical amount of sleep tends to decrease day by day from Friday to Thursday.

Explanation of Solution

Given:

PRACTICE OF STATISTICS F/AP EXAM, Chapter 1.3, Problem 120E , additional homework tip 3

The typical amount of sleep that the students get are showed by the horizontal lines in the box of the box plot and it is observed that the highest typical amount of sleep occurs on where the lowest typical amount of sleep occurs on Thursday and the typical amount of sleep tends to decrease day by day from Friday to Thursday

(d)

To determine

To find: the night was the most variation in the students slept.

(d)

Expert Solution

Answer to Problem 120E

Saturday night.

Explanation of Solution

Given:

PRACTICE OF STATISTICS F/AP EXAM, Chapter 1.3, Problem 120E , additional homework tip 4

The variation in the distribution is showed by the width between the whiskers of the box plot.

It is observe that the width between the whiskers of the whiskers of the box plot is higher for Saturday, which means that the most variation in the amount of sleep occurs on Saturday night.

Chapter 1.3, Problem 119E

Chapter 1.3, Problem 121E

Chapter 1 Solutions

PRACTICE OF STATISTICS F/AP EXAM

Ch. 1.1 - Prob. 11E Ch. 1.1 - Prob. 12E Ch. 1.1 - Prob. 13E Ch. 1.1 - Prob. 14E Ch. 1.1 - Prob. 15E Ch. 1.1 - Prob. 16E Ch. 1.1 - Prob. 17E Ch. 1.1 - Prob. 18E Ch. 1.1 - Prob. 19E Ch. 1.1 - Prob. 20E

Ch. 1.1 - Prob. 21E Ch. 1.1 - Prob. 22E Ch. 1.1 - Prob. 23E Ch. 1.1 - Prob. 24E Ch. 1.1 - Prob. 25E Ch. 1.1 - Prob. 26E Ch. 1.1 - Prob. 27E Ch. 1.1 - Prob. 28E Ch. 1.1 - Prob. 29E Ch. 1.1 - Prob. 30E Ch. 1.1 - Prob. 31E Ch. 1.1 - Prob. 32E Ch. 1.1 - Prob. 33E Ch. 1.1 - Prob. 34E Ch. 1.1 - Prob. 35E Ch. 1.1 - Prob. 36E Ch. 1.1 - Prob. 37E Ch. 1.1 - Prob. 38E Ch. 1.1 - Prob. 39E Ch. 1.1 - Prob. 40E Ch. 1.1 - Prob. 41E Ch. 1.1 - Prob. 42E Ch. 1.1 - Prob. 43E Ch. 1.1 - Prob. 44E Ch. 1.2 - Prob. 45E Ch. 1.2 - Prob. 46E Ch. 1.2 - Prob. 47E Ch. 1.2 - Prob. 48E Ch. 1.2 - Prob. 49E Ch. 1.2 - Prob. 50E Ch. 1.2 - Prob. 51E Ch. 1.2 - Prob. 52E Ch. 1.2 - Prob. 53E Ch. 1.2 - Prob. 54E Ch. 1.2 - Prob. 55E Ch. 1.2 - Prob. 56E Ch. 1.2 - Prob. 57E Ch. 1.2 - Prob. 58E Ch. 1.2 - Prob. 59E Ch. 1.2 - Prob. 60E Ch. 1.2 - Prob. 61E Ch. 1.2 - Prob. 62E Ch. 1.2 - Prob. 63E Ch. 1.2 - Prob. 64E Ch. 1.2 - Prob. 65E Ch. 1.2 - Prob. 66E Ch. 1.2 - Prob. 67E Ch. 1.2 - Prob. 68E Ch. 1.2 - Prob. 69E Ch. 1.2 - Prob. 70E Ch. 1.2 - Prob. 71E Ch. 1.2 - Prob. 72E Ch. 1.2 - Prob. 73E Ch. 1.2 - Prob. 74E Ch. 1.2 - Prob. 75E Ch. 1.2 - Prob. 76E Ch. 1.2 - Prob. 77E Ch. 1.2 - Prob. 78E Ch. 1.2 - Prob. 79E Ch. 1.2 - Prob. 80E Ch. 1.2 - Prob. 81E Ch. 1.2 - Prob. 82E Ch. 1.2 - Prob. 83E Ch. 1.2 - Prob. 84E Ch. 1.2 - Prob. 85E Ch. 1.2 - Prob. 86E Ch. 1.3 - Prob. 87E Ch. 1.3 - Prob. 88E Ch. 1.3 - Prob. 89E Ch. 1.3 - Prob. 90E Ch. 1.3 - Prob. 91E Ch. 1.3 - Prob. 92E Ch. 1.3 - Prob. 93E Ch. 1.3 - Prob. 94E Ch. 1.3 - Prob. 95E Ch. 1.3 - Prob. 96E Ch. 1.3 - Prob. 97E Ch. 1.3 - Prob. 98E Ch. 1.3 - Prob. 99E Ch. 1.3 - Prob. 100E Ch. 1.3 - Prob. 101E Ch. 1.3 - Prob. 102E Ch. 1.3 - Prob. 103E Ch. 1.3 - Prob. 104E Ch. 1.3 - Prob. 105E Ch. 1.3 - Prob. 106E Ch. 1.3 - Prob. 107E Ch. 1.3 - Prob. 108E Ch. 1.3 - Prob. 109E Ch. 1.3 - Prob. 110E Ch. 1.3 - Prob. 111E Ch. 1.3 - Prob. 112E Ch. 1.3 - Prob. 113E Ch. 1.3 - Prob. 114E Ch. 1.3 - Prob. 115E Ch. 1.3 - Prob. 116E Ch. 1.3 - Prob. 117E Ch. 1.3 - Prob. 118E Ch. 1.3 - Prob. 119E Ch. 1.3 - Prob. 120E Ch. 1.3 - Prob. 121E Ch. 1.3 - Prob. 122E Ch. 1.3 - Prob. 123E Ch. 1.3 - Prob. 124E Ch. 1.3 - Prob. 125E Ch. 1.3 - Prob. 126E Ch. 1.3 - Prob. 127E Ch. 1.3 - Prob. 128E Ch. 1 - Prob. 1E Ch. 1 - Prob. 2E Ch. 1 - Prob. 3E Ch. 1 - Prob. 4E Ch. 1 - Prob. 5E Ch. 1 - Prob. 6E Ch. 1 - Prob. 7E Ch. 1 - Prob. 8E Ch. 1 - Prob. 9E Ch. 1 - Prob. 10E Ch. 1 - Prob. R1.1RE Ch. 1 - Prob. R1.2RE Ch. 1 - Prob. R1.3RE Ch. 1 - Prob. R1.4RE Ch. 1 - Prob. R1.5RE Ch. 1 - Prob. R1.6RE Ch. 1 - Prob. R1.7RE Ch. 1 - Prob. R1.8RE Ch. 1 - Prob. R1.9RE Ch. 1 - Prob. R1.10RE Ch. 1 - Prob. T1.1SPT Ch. 1 - Prob. T1.2SPT Ch. 1 - Prob. T1.3SPT Ch. 1 - Prob. T1.4SPT Ch. 1 - Prob. T1.5SPT Ch. 1 - Prob. T1.6SPT Ch. 1 - Prob. T1.7SPT Ch. 1 - Prob. T1.8SPT Ch. 1 - Prob. T1.9SPT Ch. 1 - Prob. T1.10SPT Ch. 1 - Prob. T1.11SPT Ch. 1 - Prob. T1.12SPT Ch. 1 - Prob. T1.13SPT Ch. 1 - Prob. T1.14SPT

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