PRACTICE OF STATISTICS F/AP EXAM
PRACTICE OF STATISTICS F/AP EXAM
6th Edition
ISBN: 9781319113339
Author: Starnes
Publisher: MAC HIGHER
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Chapter 1.2, Problem 64E

a.

To determine

To explain: The reason of splitting the stems.

a.

Expert Solution
Check Mark

Explanation of Solution

Given:

The stem and leaf plot:

  PRACTICE OF STATISTICS F/AP EXAM, Chapter 1.2, Problem 64E

The stems have been split because to explain the shape of the provided distribution. If the stems are not divided the most of the data would fall on some of the stems. So, get the information about the shape of the distribution the stems have been split.

b.

To determine

To explain: The key of the provided stem plot.

b.

Expert Solution
Check Mark

Explanation of Solution

Here, 1|5 shows that 15 mg of 8 ounce is being present in the soft drink. Here, 15 means that

  1×10+5×1=15

c.

To determine

To describe: The shape of the provided distribution. Also, check if there any outlier exists in the distribution.

c.

Expert Solution
Check Mark

Explanation of Solution

The stem plot is right skewed because most of the values are lying on the right side of the plot. Thus, the distribution is skewed to the right. And, there is no gap or space between the values. It means no outliers are present.

Chapter 1 Solutions

PRACTICE OF STATISTICS F/AP EXAM

Ch. 1.1 - Prob. 21ECh. 1.1 - Prob. 22ECh. 1.1 - Prob. 23ECh. 1.1 - Prob. 24ECh. 1.1 - Prob. 25ECh. 1.1 - Prob. 26ECh. 1.1 - Prob. 27ECh. 1.1 - Prob. 28ECh. 1.1 - Prob. 29ECh. 1.1 - Prob. 30ECh. 1.1 - Prob. 31ECh. 1.1 - Prob. 32ECh. 1.1 - Prob. 33ECh. 1.1 - Prob. 34ECh. 1.1 - Prob. 35ECh. 1.1 - Prob. 36ECh. 1.1 - Prob. 37ECh. 1.1 - Prob. 38ECh. 1.1 - Prob. 39ECh. 1.1 - Prob. 40ECh. 1.1 - Prob. 41ECh. 1.1 - Prob. 42ECh. 1.1 - Prob. 43ECh. 1.1 - Prob. 44ECh. 1.2 - Prob. 45ECh. 1.2 - Prob. 46ECh. 1.2 - Prob. 47ECh. 1.2 - Prob. 48ECh. 1.2 - Prob. 49ECh. 1.2 - Prob. 50ECh. 1.2 - Prob. 51ECh. 1.2 - Prob. 52ECh. 1.2 - Prob. 53ECh. 1.2 - Prob. 54ECh. 1.2 - Prob. 55ECh. 1.2 - Prob. 56ECh. 1.2 - Prob. 57ECh. 1.2 - Prob. 58ECh. 1.2 - Prob. 59ECh. 1.2 - Prob. 60ECh. 1.2 - Prob. 61ECh. 1.2 - Prob. 62ECh. 1.2 - Prob. 63ECh. 1.2 - Prob. 64ECh. 1.2 - Prob. 65ECh. 1.2 - Prob. 66ECh. 1.2 - Prob. 67ECh. 1.2 - Prob. 68ECh. 1.2 - Prob. 69ECh. 1.2 - Prob. 70ECh. 1.2 - Prob. 71ECh. 1.2 - Prob. 72ECh. 1.2 - Prob. 73ECh. 1.2 - Prob. 74ECh. 1.2 - Prob. 75ECh. 1.2 - Prob. 76ECh. 1.2 - Prob. 77ECh. 1.2 - Prob. 78ECh. 1.2 - Prob. 79ECh. 1.2 - Prob. 80ECh. 1.2 - Prob. 81ECh. 1.2 - Prob. 82ECh. 1.2 - Prob. 83ECh. 1.2 - Prob. 84ECh. 1.2 - Prob. 85ECh. 1.2 - Prob. 86ECh. 1.3 - Prob. 87ECh. 1.3 - Prob. 88ECh. 1.3 - Prob. 89ECh. 1.3 - Prob. 90ECh. 1.3 - Prob. 91ECh. 1.3 - Prob. 92ECh. 1.3 - Prob. 93ECh. 1.3 - Prob. 94ECh. 1.3 - Prob. 95ECh. 1.3 - Prob. 96ECh. 1.3 - Prob. 97ECh. 1.3 - Prob. 98ECh. 1.3 - Prob. 99ECh. 1.3 - Prob. 100ECh. 1.3 - Prob. 101ECh. 1.3 - Prob. 102ECh. 1.3 - Prob. 103ECh. 1.3 - Prob. 104ECh. 1.3 - Prob. 105ECh. 1.3 - Prob. 106ECh. 1.3 - Prob. 107ECh. 1.3 - Prob. 108ECh. 1.3 - Prob. 109ECh. 1.3 - Prob. 110ECh. 1.3 - Prob. 111ECh. 1.3 - Prob. 112ECh. 1.3 - Prob. 113ECh. 1.3 - Prob. 114ECh. 1.3 - Prob. 115ECh. 1.3 - Prob. 116ECh. 1.3 - Prob. 117ECh. 1.3 - Prob. 118ECh. 1.3 - Prob. 119ECh. 1.3 - Prob. 120ECh. 1.3 - Prob. 121ECh. 1.3 - Prob. 122ECh. 1.3 - Prob. 123ECh. 1.3 - Prob. 124ECh. 1.3 - Prob. 125ECh. 1.3 - Prob. 126ECh. 1.3 - Prob. 127ECh. 1.3 - Prob. 128ECh. 1 - Prob. 1ECh. 1 - Prob. 2ECh. 1 - Prob. 3ECh. 1 - Prob. 4ECh. 1 - Prob. 5ECh. 1 - Prob. 6ECh. 1 - Prob. 7ECh. 1 - Prob. 8ECh. 1 - Prob. 9ECh. 1 - Prob. 10ECh. 1 - Prob. R1.1RECh. 1 - Prob. R1.2RECh. 1 - Prob. R1.3RECh. 1 - Prob. R1.4RECh. 1 - Prob. R1.5RECh. 1 - Prob. R1.6RECh. 1 - Prob. R1.7RECh. 1 - Prob. R1.8RECh. 1 - Prob. R1.9RECh. 1 - Prob. R1.10RECh. 1 - Prob. T1.1SPTCh. 1 - Prob. T1.2SPTCh. 1 - Prob. T1.3SPTCh. 1 - Prob. T1.4SPTCh. 1 - Prob. T1.5SPTCh. 1 - Prob. T1.6SPTCh. 1 - Prob. T1.7SPTCh. 1 - Prob. T1.8SPTCh. 1 - Prob. T1.9SPTCh. 1 - Prob. T1.10SPTCh. 1 - Prob. T1.11SPTCh. 1 - Prob. T1.12SPTCh. 1 - Prob. T1.13SPTCh. 1 - Prob. T1.14SPT
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