Interpretation:

The function of the regulators on the air tanks by scuba divers is to be explained.

Concept introduction:

Scuba diving is underwater diving with the help of scuba. Scuba is a self contained underwater breathing apparatus. This apparatus has air tank which containregulators.

Expert Solution & Answer

Answer to Problem 117A

The function of scuba diving regulator is to decrease the pressure of air in the air tank according to the requirement.

Explanation of Solution

The reduction of air pressure is done in two stages:

First stage:

At first stage, pressure of air is reduced to intermediate pressure and released into a hose which shifts into second stage.

Second stage:

At second stage, pressure of air is reduced to ambient pressure so that diver can breathe comfortably. It also allows air to flow to the mouth only when the diver inhales.

Conclusion

Thus, the function of regulator is to decrease the pressure of air in the air tank in the scuba diving as per the requirement.

Chapter 13, Problem 116A

Chapter 13, Problem 118A

Chapter 13 Solutions

Chemistry: Matter and Change

Ch. 13.1 - Prob. 1PP Ch. 13.1 - Prob. 2PP Ch. 13.1 - Prob. 3PP Ch. 13.1 - Prob. 4PP Ch. 13.1 - Prob. 5PP Ch. 13.1 - Prob. 6PP Ch. 13.1 - Prob. 7PP Ch. 13.1 - Prob. 8PP Ch. 13.1 - Prob. 9PP Ch. 13.1 - Prob. 10PP

Ch. 13.1 - Prob. 11PP Ch. 13.1 - Prob. 12PP Ch. 13.1 - Prob. 13PP Ch. 13.1 - Prob. 14SSC Ch. 13.1 - Prob. 15SSC Ch. 13.1 - Prob. 16SSC Ch. 13.1 - Prob. 17SSC Ch. 13.1 - Prob. 18SSC Ch. 13.1 - Prob. 19SSC Ch. 13.2 - Prob. 20PP Ch. 13.2 - Prob. 21PP Ch. 13.2 - Prob. 22PP Ch. 13.2 - Prob. 23PP Ch. 13.2 - Prob. 24PP Ch. 13.2 - Prob. 25PP Ch. 13.2 - Prob. 26PP Ch. 13.2 - Prob. 27PP Ch. 13.2 - Prob. 28PP Ch. 13.2 - Prob. 29PP Ch. 13.2 - Prob. 30PP Ch. 13.2 - Prob. 31SSC Ch. 13.2 - Prob. 32SSC Ch. 13.2 - Prob. 33SSC Ch. 13.2 - Prob. 34SSC Ch. 13.2 - Prob. 35SSC Ch. 13.2 - Prob. 36SSC Ch. 13.2 - Prob. 37SSC Ch. 13.3 - Prob. 38PP Ch. 13.3 - Prob. 39PP Ch. 13.3 - Prob. 40PP Ch. 13.3 - Prob. 41PP Ch. 13.3 - Prob. 42PP Ch. 13.3 - Prob. 43PP Ch. 13.3 - Prob. 44PP Ch. 13.3 - Prob. 45PP Ch. 13.3 - Prob. 46SSC Ch. 13.3 - Prob. 47SSC Ch. 13.3 - Prob. 48SSC Ch. 13.3 - Prob. 49SSC Ch. 13 - Prob. 50A Ch. 13 - Prob. 51A Ch. 13 - Prob. 52A Ch. 13 - Prob. 53A Ch. 13 - Prob. 54A Ch. 13 - Prob. 55A Ch. 13 - Prob. 56A Ch. 13 - Prob. 57A Ch. 13 - Prob. 58A Ch. 13 - Prob. 59A Ch. 13 - Prob. 60A Ch. 13 - Prob. 61A Ch. 13 - Prob. 62A Ch. 13 - Prob. 63A Ch. 13 - Prob. 64A Ch. 13 - Prob. 65A Ch. 13 - Prob. 66A Ch. 13 - Prob. 67A Ch. 13 - Prob. 68A Ch. 13 - Prob. 69A Ch. 13 - Prob. 70A Ch. 13 - Prob. 71A Ch. 13 - Prob. 72A Ch. 13 - Prob. 73A Ch. 13 - Prob. 74A Ch. 13 - Prob. 75A Ch. 13 - Prob. 76A Ch. 13 - Prob. 77A Ch. 13 - Prob. 78A Ch. 13 - Prob. 79A Ch. 13 - Prob. 80A Ch. 13 - Prob. 81A Ch. 13 - Prob. 82A Ch. 13 - Prob. 83A Ch. 13 - Prob. 84A Ch. 13 - Prob. 85A Ch. 13 - Prob. 86A Ch. 13 - Prob. 87A Ch. 13 - Prob. 88A Ch. 13 - Prob. 89A Ch. 13 - Prob. 90A Ch. 13 - Prob. 91A Ch. 13 - Prob. 92A Ch. 13 - Prob. 93A Ch. 13 - Prob. 94A Ch. 13 - Oxygen Consumption If 5.00 L of hydrogen...Ch. 13 - Prob. 96A Ch. 13 - If 2.33 L of propane at 24°C and 67.2 kPa is...Ch. 13 - Prob. 98A Ch. 13 - Prob. 99A Ch. 13 - Prob. 100A Ch. 13 - Prob. 101A Ch. 13 - Apply Calculate the pressure of (4.671022)...Ch. 13 - Analyze When nitroglycerin (C3H5N3O9) explodes,...Ch. 13 - Prob. 104A Ch. 13 - Prob. 105A Ch. 13 - Prob. 106A Ch. 13 - Prob. 107A Ch. 13 - Prob. 108A Ch. 13 - Prob. 109A Ch. 13 - Prob. 110A Ch. 13 - Prob. 111A Ch. 13 - Prob. 112A Ch. 13 - Prob. 113A Ch. 13 - Prob. 114A Ch. 13 - Prob. 115A Ch. 13 - Prob. 116A Ch. 13 - Prob. 117A Ch. 13 - Prob. 118A Ch. 13 - Prob. 119A Ch. 13 - Prob. 1STP Ch. 13 - Prob. 2STP Ch. 13 - Prob. 3STP Ch. 13 - Prob. 4STP Ch. 13 - Prob. 5STP Ch. 13 - Prob. 6STP Ch. 13 - Prob. 7STP Ch. 13 - Prob. 8STP Ch. 13 - Prob. 9STP Ch. 13 - Prob. 10STP Ch. 13 - Prob. 11STP Ch. 13 - Prob. 12STP Ch. 13 - Prob. 13STP Ch. 13 - Prob. 14STP

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