Chapter 13, Problem 73A

Interpretation Introduction

Interpretation:

The volume occupied by given mass of two gases at STP needs to be determined.

Concept introduction:

Stoichiometry concepts and Avogadro’s Law are used to calculate the result.

Answer to Problem 73A

The volume occupied by given amount of Nitrogen gas is more than volume occupied by propane gas.

Explanation of Solution

According to Avogadro’s principle,

One mol of every substance occupies 22.4 L gas at STP.

Hence,

$\begin{array}{l}1mol{C}_3{H}_{8}occupies22.4LatSTP\\ \therefore 44g{C}_3{H}_{8}occupies22.4LatSTP\\ So0.52Kg(0.52\times {10}^3)willoccupy=22.4\times \frac{0.52\times {10}^3}{44}\\ =264.7L\end{array}$

$\begin{array}{l}1mol{N}_{2}occupies22.4LatSTP\\ \therefore 28g{N}_{2}occupies22.4LatSTP\\ So0.38Kg(0.38\times {10}^3)willoccupy=22.4\times \frac{0.38\times {10}^3}{28}\\ =304L\end{array}$

Thus nitrogen gas occupies more volume.

Conclusion

The given amount of Nitrogen gas will occupy more volume than given amount of propane.