Chemistry: Matter and Change
1st Edition
ISBN: 9780078746376
Author: Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom
Publisher: Glencoe/McGraw-Hill School Pub Co
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Concept explainers
Question
Chapter 13, Problem 106A
Interpretation Introduction
Interpretation:
The value given by
Concept introduction:
Kinetic − molecular theory can be applied to give the result.
Expert Solution & Answer
Answer to Problem 106A
Higher pressure is calculated by ideal
Explanation of Solution
At high pressure, the molecules of gas come closer. Due to which force of attraction between the particles increases which decreases the force of collision on the walls of container. Hence, actual pressure is lower than the value of pressure given by ideal gas law.
At low temperature, kinetic energy of gas molecules will decrease which will lower the pressure on the walls of the container.
Conclusion
Higher pressure is calculated by ideal gas law at high pressures and low temperatures.
Chapter 13 Solutions
Chemistry: Matter and Change
Ch. 13.1 - Prob. 1PPCh. 13.1 - Prob. 2PPCh. 13.1 - Prob. 3PPCh. 13.1 - Prob. 4PPCh. 13.1 - Prob. 5PPCh. 13.1 - Prob. 6PPCh. 13.1 - Prob. 7PPCh. 13.1 - Prob. 8PPCh. 13.1 - Prob. 9PPCh. 13.1 - Prob. 10PP
Ch. 13.1 - Prob. 11PPCh. 13.1 - Prob. 12PPCh. 13.1 - Prob. 13PPCh. 13.1 - Prob. 14SSCCh. 13.1 - Prob. 15SSCCh. 13.1 - Prob. 16SSCCh. 13.1 - Prob. 17SSCCh. 13.1 - Prob. 18SSCCh. 13.1 - Prob. 19SSCCh. 13.2 - Prob. 20PPCh. 13.2 - Prob. 21PPCh. 13.2 - Prob. 22PPCh. 13.2 - Prob. 23PPCh. 13.2 - Prob. 24PPCh. 13.2 - Prob. 25PPCh. 13.2 - Prob. 26PPCh. 13.2 - Prob. 27PPCh. 13.2 - Prob. 28PPCh. 13.2 - Prob. 29PPCh. 13.2 - Prob. 30PPCh. 13.2 - Prob. 31SSCCh. 13.2 - Prob. 32SSCCh. 13.2 - Prob. 33SSCCh. 13.2 - Prob. 34SSCCh. 13.2 - Prob. 35SSCCh. 13.2 - Prob. 36SSCCh. 13.2 - Prob. 37SSCCh. 13.3 - Prob. 38PPCh. 13.3 - Prob. 39PPCh. 13.3 - Prob. 40PPCh. 13.3 - Prob. 41PPCh. 13.3 - Prob. 42PPCh. 13.3 - Prob. 43PPCh. 13.3 - Prob. 44PPCh. 13.3 - Prob. 45PPCh. 13.3 - Prob. 46SSCCh. 13.3 - Prob. 47SSCCh. 13.3 - Prob. 48SSCCh. 13.3 - Prob. 49SSCCh. 13 - Prob. 50ACh. 13 - Prob. 51ACh. 13 - Prob. 52ACh. 13 - Prob. 53ACh. 13 - Prob. 54ACh. 13 - Prob. 55ACh. 13 - Prob. 56ACh. 13 - Prob. 57ACh. 13 - Prob. 58ACh. 13 - Prob. 59ACh. 13 - Prob. 60ACh. 13 - Prob. 61ACh. 13 - Prob. 62ACh. 13 - Prob. 63ACh. 13 - Prob. 64ACh. 13 - Prob. 65ACh. 13 - Prob. 66ACh. 13 - Prob. 67ACh. 13 - Prob. 68ACh. 13 - Prob. 69ACh. 13 - Prob. 70ACh. 13 - Prob. 71ACh. 13 - Prob. 72ACh. 13 - Prob. 73ACh. 13 - Prob. 74ACh. 13 - Prob. 75ACh. 13 - Prob. 76ACh. 13 - Prob. 77ACh. 13 - Prob. 78ACh. 13 - Prob. 79ACh. 13 - Prob. 80ACh. 13 - Prob. 81ACh. 13 - Prob. 82ACh. 13 - Prob. 83ACh. 13 - Prob. 84ACh. 13 - Prob. 85ACh. 13 - Prob. 86ACh. 13 - Prob. 87ACh. 13 - Prob. 88ACh. 13 - Prob. 89ACh. 13 - Prob. 90ACh. 13 - Prob. 91ACh. 13 - Prob. 92ACh. 13 - Prob. 93ACh. 13 - Prob. 94ACh. 13 - Oxygen Consumption If 5.00 L of hydrogen...Ch. 13 - Prob. 96ACh. 13 - If 2.33 L of propane at 24°C and 67.2 kPa is...Ch. 13 - Prob. 98ACh. 13 - Prob. 99ACh. 13 - Prob. 100ACh. 13 - Prob. 101ACh. 13 - Apply Calculate the pressure of (4.671022)...Ch. 13 - Analyze When nitroglycerin (C3H5N3O9) explodes,...Ch. 13 - Prob. 104ACh. 13 - Prob. 105ACh. 13 - Prob. 106ACh. 13 - Prob. 107ACh. 13 - Prob. 108ACh. 13 - Prob. 109ACh. 13 - Prob. 110ACh. 13 - Prob. 111ACh. 13 - Prob. 112ACh. 13 - Prob. 113ACh. 13 - Prob. 114ACh. 13 - Prob. 115ACh. 13 - Prob. 116ACh. 13 - Prob. 117ACh. 13 - Prob. 118ACh. 13 - Prob. 119ACh. 13 - Prob. 1STPCh. 13 - Prob. 2STPCh. 13 - Prob. 3STPCh. 13 - Prob. 4STPCh. 13 - Prob. 5STPCh. 13 - Prob. 6STPCh. 13 - Prob. 7STPCh. 13 - Prob. 8STPCh. 13 - Prob. 9STPCh. 13 - Prob. 10STPCh. 13 - Prob. 11STPCh. 13 - Prob. 12STPCh. 13 - Prob. 13STPCh. 13 - Prob. 14STP
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