Chapter 13, Problem 91A

Interpretation Introduction

(a)

Interpretation:

The balanced chemical equation of combustion of methane is to be written.

Concept introduction:

In a combustion reaction of hydrocarbon, carbon dioxide and water are formed.

Answer to Problem 91A

Methane undergoes complete combustion by oxygen to form carbon dioxide and water

${\text{CH}}_4{\text{+2O}}_2\to 2H_{\text{2}}{\text{O+CO}}_2$

Explanation of Solution

The reaction can be explained as:

One mol of methane reacts with two mol oxygen to form two mol water and one mol carbon dioxide.

(b)

Interpretation Introduction

Interpretation:

The volume ratio of methane to carbon water is to be calculated.

Concept introduction:

Stoichiometry concepts are used for it.

Answer to Problem 91A

$\mathrm{Volume}ratioofC{H}_{4}and{H}_{2}O=1:2$

Explanation of Solution

Volume ratios are calculated by first balancing the reaction then using coefficients of reactant and product as volume equivalents.

The balanced chemical equation is as follows:

${\text{CH}}_4{\text{+2O}}_2\to 2H_{\text{2}}{\text{O+CO}}_2$

Here, the volume of ratio of methane to water is 1:2.