Chapter 12.7, Problem 45CCR

To determine

To find: The value of $P\left(\text{Not}\text{prime}\right)$ and check nature of the event.

Answer to Problem 45CCR

The value of $P\left(\text{Not}\text{prime}\right)$ is $\frac{1}{2}$ and the event is equally likely.

Explanation of Solution

Given information:

A six sided number cube.

Calculation:

Since, a six-sided number cube has six number with three prime numbers 2, 3, and 5 and three non-prime numbers 1, 4, and 6.

Calculate the value of $P\left(\text{Not}\text{prime}\right)$ .

  $\begin{array}{c}P\left(\text{Not}\text{prime}\right)=\frac{3}{6}\\ =\frac{1}{2}\text{or}50\%\end{array}$

From the above, it is clear that the event is equally likely.

Conclusion:

Therefore, the value of $P\left(\text{Not}\text{prime}\right)$ is $\frac{1}{2}$ and the event is equally likely.