Chapter 12.8, Problem 30CCR

To determine

To find : Volume of rough, to nearest tenth.

Answer to Problem 30CCR

  $117.8{\text{ ft}}^{\text{3}}$

Explanation of Solution

Given information :

The given information is, a rough is shown.

Formula Used:

Volume of cylinder = $\pi r^{2}h$

  

Calculation :

  $\begin{array}{l}r=2.5\text{ ft}\text{., }h=12\text{ ft}\text{.}\\ V=\pi r^{2}h\\ $ V=\pi {(2.5)}^2(12)=235.619{\text{ ft}}^{\text{3}}$\end{array}$

Half of volume $=\frac{235.619}{2}=117.809{\text{ ft}}^{\text{3}}$

To nearest tenth, $117.8{\text{ ft}}^{\text{3}}$