Chapter 12.3, Problem 20IP

To determine

To find: Total area of given structure

Answer to Problem 20IP

  ${\text{135feet}}^{\text{2}}$

Explanation of Solution

Given:

We know that

Base of triangle=8ft, Height of triangle =15ft

Formula: $\text{area of triangle=}\frac{\text{1}}{\text{2}}\text{×b×h,area of trapizium=}\frac{\text{1}}{\text{2}}\text{(a+b)h}$

Calculation: Required area = area of trapezium −area of triangle

  $\begin{array}{l}\text{=}\frac{\text{1}}{\text{2}}\text{×8×15-}\frac{\text{1}}{\text{2}}\text{(18+8)15}\\ \text{=}\frac{\text{1}}{\text{2}}\text{×26×15-4×15}\\ \text{=195-60}\\ {\text{=135feet}}^{\text{2}}\end{array}$