Chapter 12.3, Problem 5GP

(a)

To determine

To find: Total area of given structure

Answer to Problem 5GP

  ${\text{58feet}}^{\text{2}}$

Explanation of Solution

Given:

All dimensions of structure are given

Formula Used:

  $\text{area of trapezium=}\frac{\text{1}}{\text{2}}\text{(a+b)h}$

  $\text{area of rectangle=lenfth}\times \text{breadth}$

Calculation:

  $\begin{array}{l}{\text{area=(area)}}_{\text{1}}{\text{+(area)}}_{\text{2}}\\ \text{=}\frac{\text{1}}{\text{2}}\text{(a+b)h+×l×b}\\ \text{=}\frac{\text{1}}{\text{2}}\text{(4+13)4+×4×6}\\ \text{=34+24}\\ {\text{=58feet}}^{\text{2}}\end{array}$

(b)

To determine

To find: Total cost to cover given structure

Answer to Problem 5GP

  $241.66\$$

Explanation of Solution

Given:

We know that , Cost of 6 feet² is 25$

Calculation: $\because Costtocover6fee{t}^2=25\$$

  $\therefore Costtocover\text{ 1}fee{t}^2=\frac{25}{6}\$$

  $\begin{array}{l}\therefore Costtocover\text{ 58}fee{t}^2=\frac{25}{6}\times 58\\ =241.66\$\end{array}$