Chapter 12.5, Problem 39CCR

To determine

To find : Area of given figure.

Answer to Problem 39CCR

Area = $228.6{\text{ mm}}^{\text{2}}$

Explanation of Solution

Given information :

The given information is

  

Formula Used:

Area of triangle = $\frac{1}{2}\times b\times h$

Area of semicircle = $\frac{\pi r^2}{2}$

Calculation :

Total Area = Area of triangle + Area of semicircle

  $\begin{array}{l}=\frac{1}{2}\times 16\times 16+\frac{1}{2}\times \frac{22}{7}\times 8\times 8\\ =128+\frac{11\times 64}{7}\\ =128+100.57\\ =228.57{\text{ mm}}^{\text{2}}\\ \approx 228.6{\text{mm}}^{\text{2}}\end{array}$