Chapter 12.6, Problem 16IP

To determine

To find : Volume of given figure.

Answer to Problem 16IP

  $8518.57{\text{ in}}^{\text{3}}$

Explanation of Solution

Given information :

The given information is

  

We know that length ( $l$ ) = $30$ in., width ( $w$ ) = $9$ in., height ( $h$ ) = $17$ in., radius = $\frac{l}{2}=12.5$ in and height = $4$ in.

Formula Used:

Volume of cylinder = $\pi r^{2}h$

Calculation :

Volume of given figure

= Volume of Cuboid + $2$ × (Volume of Cylinder)

  $\begin{array}{l}=(30\times 9\times 17)+2\times (3.14\times 12.5\times 12.5\times 4)\\ =4590+3928.57\\ =8518.57{\text{ in}}^{\text{3}}\end{array}$

Hence, volume of given figure = $8518.57{\text{ in}}^{\text{3}}$