Chapter 12.3, Problem 12IP

(a)

To determine

To find: The area of pool’s floor

Answer to Problem 12IP

  $388.75fee{t}^2$

Explanation of Solution

Given:

All sides length of swimming pool are given

Formula: $\text{area of trapezium=}\frac{\text{1}}{\text{2}}\left(\text{sum of parallel sides}\right)\text{×height}$

Calculation:

  $\begin{array}{l}{\text{(area)}}_{\text{1}}\text{=}\frac{\text{1}}{\text{2}}\text{(16+15)×14}\\ \text{=}\frac{\text{1}}{\text{2}}{\text{×350ft}}^{\text{2}}\\ {\text{(area)}}_{\text{2}}\text{=}\frac{\text{1}}{\text{2}}\text{(11+}\frac{\text{35}}{\text{2}}\text{)×15}\\ \text{=}\frac{\text{1}}{\text{2}}\text{×427}{\text{.5ft}}^{\text{2}}\\ {\text{totalarea=(area)}}_{\text{1}}{\text{+(area)}}_{\text{2}}\\ \text{=}\frac{\text{1}}{\text{2}}\text{(350+427}\text{.5)}\\ \text{=388}{\text{.75feet}}^{\text{2}}\end{array}$

(b)

To determine

To find: total cost of pool

Answer to Problem 12IP

  $660.87\$$

Explanation of Solution

Given We know that cost of 1 ${\text{feet}}^{\text{2}}$ is 1.7$

Calculation:

  $\begin{array}{l}\therefore {\text{ cost of 1feet}}^{\text{2}}\text{area = 1}\text{.7\$}\\ \therefore \text{cost of 388}{\text{.75feet}}^{\text{2}}\text{area = 388}\text{.75×1}\text{.7}\\ \text{=660}\text{.87\$}\end{array}$