Chapter 12.6, Problem 5GP

To determine

To find : Volume of Peg.

Answer to Problem 5GP

  $22{\text{ cm}}^{\text{3}}$

Explanation of Solution

Given information :

The given information is

  

Formula Used:

Volume of cylinder = $\pi r^{2}h$

Calculation :

Volume for 1st Cylinder = $\pi r_1^2{h}_1$

Where, $r_1=2$ cm and $h_1=1$ cm

Volume = $\frac{88}{7}{\text{cm}}^3$

Volume for $2^{\text{nd}}$ cylinder = $\pi r_2^2{h}_2$

  $r_2=1$ cm and $h_2=3$ cm

Volume = $\frac{66}{7}{\text{cm}}^3$

Volume of Peg = $\frac{88}{7}+\frac{66}{7}=\frac{154}{7}=22{\text{ cm}}^{\text{3}}$