Chapter 12.6, Problem 18IP

To determine

To find : Volume of mail box.

Answer to Problem 18IP

  $1596.31{\text{ in}}^{\text{3}}$

Explanation of Solution

Given information :

  

We know that, length = $6.75$ in., width = $6.375$ in., height = $20.25$ in and

Radius = $\frac{\text{diameter}}{\text{2}}=\frac{6.75}{2}=3.375\text{ in}\text{.}$

Formula Used:

Volume of rectangular box = $l\times w\times h$

Volume of half cylinder = $\frac{\pi r^{2}h}{2}$

Calculation :

Volume of mail box = $l\times w\times h+\frac{\pi r^{2}h}{2}$

  $\begin{array}{l}=(6.72\times 6.375\times 20.25)+\frac{(3.14)\times {(3.375)}^2(20.25)}{2}\\ =871.38+724.93\\ =1596.31{\text{ in}}^{\text{3}}\end{array}$

Volume of mail box = $1596.31{\text{in}}^3$