Chapter 12.3, Problem 13IP

(a)

To determine

To find: Area of space to be carpeted

Answer to Problem 13IP

  $\text{354sqft}$

Explanation of Solution

Given: All dimensions of given structure are given

Formula:

  $\text{Area of trapezium=}\frac{\text{1}}{\text{2}}\left(\text{sum of parallel sides}\right)\text{×height}$

Calculation:

  $\begin{array}{l}{\text{(Area)}}_{\text{1}}\text{=}\frac{\text{1}}{\text{2}}\text{(10+16)×6}\\ \text{=26×3}\\ {\text{=78ft}}^{\text{2}}\\ {\text{(Area)}}_{\text{2}}\text{=23×12}\\ {\text{=276ft}}^{\text{2}}\\ {\text{total area=(area)}}_{\text{1}}{\text{+(area)}}_{\text{2}}\\ \text{=78+276}\\ \text{=354sq-ft}\end{array}$

(b)

To determine

To find: Total cost of carpet

Answer to Problem 13IP

  $796.5\$$

Explanation of Solution

Given:

Cost of carpeting one square feet is $2.25\$$

Calculation: $\therefore \text{cost of 1 square feet=2}\text{.25\$}$

  $\because \text{cost of 354 sq-ft=354×2}\text{.25=796}\text{.5\$}$