Chapter 12.8, Problem 21HP

To determine

To sketch : Two prisms such that one has a greater volume and other has a greater surface area.

Answer to Problem 21HP

Rectangular prisms of sides $4$ ft. and $12$ ft. respectively.

Explanation of Solution

Given information :

The given information is, Two prisms with real world emits.

Formula Used:

Surface Area = $6\times {(\text{side})}^2$

Volume = length × width × height

  

Calculation :

  $\begin{array}{ll}\text{Prism-I}\hfill & \text{Prism-II}\hfill \\ \begin{array}{l}{\text{Surface Area = 96 ft}}^{\text{2}}\\ {\text{Volume = 64 ft}}^{\text{3}}\end{array}\hfill & \begin{array}{l}{\text{Surface Area = 864 ft}}^{\text{2}}\\ {\text{Volume = 1728 ft}}^{\text{3}}\end{array}\hfill \end{array}$

Prism-I has greater surface area and Prism-II has greater volume.