Chapter 12.8, Problem 5IP

To determine

To find : Lateral and surface area of each prism.

Answer to Problem 5IP

  $3.84{\text{ cm}}^{\text{2}}$ and $4.8{\text{ cm}}^{\text{2}}$

Explanation of Solution

Given information :

The given information is, shown figure is prism.

  

Formula Used:

Total surface area, T.S.A. = $ph+2B$ , where $p$ is perimeter $B$ is area of base, and $h$ is height of pron.

Calculation :

Perimeter, $p$ = Sum of bases = $(1+1+1.2)=3.2$ cm

Lateral Surface Area = $3.2(1.2)=3.84{\text{cm}}^{\text{2}}$

2(Base Surface Area) = $2\times \frac{1}{2}(1.2\times 0.8)=0.96{\text{ cm}}^{\text{2}}$

Lateral Surface area is $3.84{\text{ cm}}^{\text{2}}$ and

Total Surface T.S.A. = $(3.84+0.96)=4.8{\text{cm}}^{\text{2}}$