Chapter 12.3, Problem 4GP

To determine

To find: Total area of given structure

Answer to Problem 4GP

  $\text{100}{\text{.28m}}^{\text{2}}$

Explanation of Solution

Given: All dimension of structure are given

Formula: $areaofcircle=\pi r^2$, $areaof\text{ rectangle=l}\times \text{b}$

Calculation: $totalarea=\frac{1}{2}\times \pi r_1^2+\frac{1}{2}\times \pi r_2^2+l\times b$

  $\begin{array}{l}\text{=}\frac{\text{1}}{\text{2}}\text{×}\frac{\text{22}}{\text{7}}{\text{×3}}^{\text{2}}\text{+}\frac{\text{1}}{\text{2}}\text{×}\frac{\text{22}}{\text{7}}{\text{×3}}^{\text{2}}\text{+12×6}\\ \text{=}\frac{\text{22}}{\text{7}}{\text{×3}}^{\text{2}}\text{+12×6}\\ \text{=}\frac{\text{198}}{\text{7}}\text{+72}\\ \text{=100}{\text{.28m}}^{\text{2}}\end{array}$