a.
To calculate: The volume of a pyramid which has a square base and height of 12.
a.

Answer to Problem 3PSA
The volume of a pyramid is 400 .
Explanation of Solution
Given information:
Base of pyramid = 10,
Height of pyramid h = 12,
Formula used:
Volume of pyramid =13B×h
B = Base area of pyramid and h = height of pyramid
Area of square: A=s2
s = side of square
Calculation:
B=ASquare=(10)2B=ASquare=100
VPyramid=13×B×hVPyramid=13×100×12VPyramid=400
b.
To find: The total area of a pyramid which has a square base of side 10.
b.

Answer to Problem 3PSA
The total area of a pyramid is 360 .
Explanation of Solution
Given information:
Base of pyramid = 10,
Height of pyramid h = 12,
Formula used:
The below theorem is used:
Pythagoras theorem states that “In a right angled
In right
a2+b2= c2
Area of triangle: A=12×b×h
b = base of triangle
h = height of triangle Area of square: A=s2
s = side of square
Calculation:
Side AC can be calculated by applying Pythagoras Theorem.
In right angled triangle ABC , we get
(AC)2=(AB)2+(BC)2(AC)2=(12)2+(5)2BC=102=5(AC)2=144+25(AC)2=169AC=√169AC=13
B=ASquare=(10)2B=ASquare=100
Lateral area = Area of triangle =12×b×h
Lateral area =12×10×13
Lateral area =65
There are four triangles.
Total Area =4× Lateral area + B
Total Area =4× 65 + 100
Total Area =260+100
Total Area =360
Chapter 12 Solutions
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