Essentials of Materials Science and Engineering, SI Edition
Essentials of Materials Science and Engineering, SI Edition
4th Edition
ISBN: 9781337672078
Author: ASKELAND, Donald R., WRIGHT, Wendelin J.
Publisher: Cengage Learning
Question
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Chapter 12, Problem 12.63P
Interpretation Introduction

(a)

Interpretation:

The temperature at which austenite begins to transform needs to be determined.

Concept Introduction:

Austenite is defined as a gamma-phase iron, it is a metallic, non-magnetic iron allotrope or a solid solution of iron, containing an alloying element. Austenite which is known to exist above the eutectoid temperature of 1000K of plain carbon steel. Other alloys of the steel contain different eutectoid temperatures. Austenite can remain stable at room temperature only in the presence of austenite stability elements, e.g. Ni in adequate quantity.

Expert Solution
Check Mark

Answer to Problem 12.63P

The temperatutre at which austenite will transform in Fe- 1.15% C alloy is 880°C.

Explanation of Solution

  Essentials of Materials Science and Engineering, SI Edition, Chapter 12, Problem 12.63P , additional homework tip  1

From the diagram cited above, the temperature at which austenite will start transforming on cooling in the Fe 1.15% C alloy is calculated as 880°C.

Interpretation Introduction

(b)

Interpretation:

The primary microconstituents that are formed needs to be determined.

Concept Introduction:

The microconstituent of iron carbide includes austenite ( γ ), ferrite, etc. austenite is a solid solution formed from ferrite and iron carbide in gamma iron. It forms when the percentage of carbon in steel is up to 1.8% at 1130 ° C. Austenite starts converting into pearlite and ferrite when it cools below 723 ° C.

Expert Solution
Check Mark

Answer to Problem 12.63P

The primary micro constituents that is formed in the alloy is primary Fe3C.

Explanation of Solution

  Essentials of Materials Science and Engineering, SI Edition, Chapter 12, Problem 12.63P , additional homework tip  2

From the diagram mentioned above the microconstituent which is formed in the Fe- 1.15%C alloy is primary Fe3C.

Interpretation Introduction

(c)

Interpretation:

The amount and composition of phase at 728°C needs to be determined.

Concept Introduction:

The plain iron-carbon alloys contain the amount of steel between 0.002% and 2.14 % by weight. At atmospheric pressure, the phases of iron plays a vital role because of the differences in carbon which forms different types of steel. High pressure phases of iron are significant as the prototype of the solid parts regarding planetary cores. The standard pressure phases are as follows:

1) Delta iron

2) Gamma iron/ austenite

3) Beta iron

4) Alpha iron

Expert Solution
Check Mark

Answer to Problem 12.63P

The amount and composition of phases in Fe- 1.15%C are 6.4% and 93.6%.

Explanation of Solution

  Essentials of Materials Science and Engineering, SI Edition, Chapter 12, Problem 12.63P , additional homework tip  3

Draw a line at which passes through Fe3Cand ofFe3C and r.

  %Fe3C=(%Fe-1.15%C-r%c%Fe3C-r%C×100)=1.15-0.776.67-0.77×100%Fe3C=6.4%%r=100-6.4

Interpretation Introduction

(d)

Interpretation:

The amount and composition of phases at 726°C needs to be determined.

Concept Introduction:

The plain iron-carbon alloys contain the amount of steel between 0.002% and 2.14 % by weight. At atmospheric pressure, the phases of iron plays a vital role because of the differences in carbon which forms different types of steel. High pressure phases of iron are significant as the prototype of the solid parts regarding planetary cores. The standard pressure phases are as follows:

1) Delta iron

2) Gamma iron/ austenite

3) Beta iron

4) Alpha iron

Expert Solution
Check Mark

Answer to Problem 12.63P

The amount and composition of phases at 726°C are 83% and 17%.

Explanation of Solution

  Essentials of Materials Science and Engineering, SI Edition, Chapter 12, Problem 12.63P , additional homework tip  4

Based on the digram we have the formula as mentioned above,

  %α=(%Fe3C-Fe-1.15%C%Fe3C-α%C×100)%α=6.77-1.156.77-0.0218×100%α=83%%Fe3C=100-83=17%

Interpretation Introduction

(e)

Interpretation:

The amount and composition of microconstituent at 726°C needs to be determined.

Concept Introduction:

The plain iron-carbon alloys contain the amount of steel between 0.002% and 2.14 % by weight. At atmospheric pressure, the phases of iron plays a vital role because of the differences in carbon which forms different types of steel. High pressure phases of iron are significant as the prototype of the solid parts regarding planetary cores. The standard pressure phases are as follows:

1) Delta iron

2) Gamma iron/ austenite

3) Beta iron

4) Alpha iron

Expert Solution
Check Mark

Answer to Problem 12.63P

The amount and composition of microconstituent are 726°C and 0.77%C.

Explanation of Solution

  Essentials of Materials Science and Engineering, SI Edition, Chapter 12, Problem 12.63P , additional homework tip  5

Based on the diagram mentioned above the microconstituent whichare present in the alloy at 726°C are primary Fe3C and pearlite.

The amount of primary Fe3C and composition are as follows:

Primary Fe3C= 6.67%C

% primary Fe3C= 6.4%

The amount and composition of pearlite are:

Pearlite= 0.77%C

% pearlite= 93.6%

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Chapter 12 Solutions

Essentials of Materials Science and Engineering, SI Edition

Ch. 12 - Prob. 12.11PCh. 12 - Prob. 12.12PCh. 12 - Prob. 12.13PCh. 12 - Prob. 12.14PCh. 12 - Prob. 12.15PCh. 12 - Prob. 12.16PCh. 12 - Prob. 12.17PCh. 12 - Prob. 12.18PCh. 12 - Prob. 12.19PCh. 12 - Prob. 12.20PCh. 12 - Prob. 12.21PCh. 12 - Prob. 12.22PCh. 12 - Prob. 12.23PCh. 12 - Prob. 12.24PCh. 12 - Prob. 12.25PCh. 12 - Prob. 12.26PCh. 12 - Prob. 12.27PCh. 12 - Prob. 12.28PCh. 12 - Prob. 12.29PCh. 12 - Prob. 12.30PCh. 12 - Prob. 12.31PCh. 12 - Prob. 12.32PCh. 12 - Prob. 12.33PCh. 12 - Prob. 12.34PCh. 12 - Prob. 12.35PCh. 12 - Prob. 12.36PCh. 12 - Prob. 12.37PCh. 12 - Prob. 12.38PCh. 12 - Prob. 12.39PCh. 12 - Prob. 12.40PCh. 12 - Prob. 12.41PCh. 12 - Prob. 12.42PCh. 12 - Prob. 12.43PCh. 12 - Prob. 12.44PCh. 12 - Prob. 12.45PCh. 12 - Prob. 12.46PCh. 12 - Prob. 12.47PCh. 12 - Prob. 12.48PCh. 12 - Prob. 12.49PCh. 12 - Prob. 12.50PCh. 12 - Prob. 12.51PCh. 12 - Prob. 12.52PCh. 12 - Prob. 12.53PCh. 12 - Prob. 12.54PCh. 12 - Prob. 12.55PCh. 12 - Prob. 12.56PCh. 12 - Prob. 12.57PCh. 12 - Prob. 12.58PCh. 12 - Prob. 12.59PCh. 12 - Prob. 12.60PCh. 12 - Prob. 12.61PCh. 12 - Prob. 12.62PCh. 12 - Prob. 12.63PCh. 12 - Prob. 12.64PCh. 12 - Prob. 12.65PCh. 12 - Prob. 12.66PCh. 12 - Prob. 12.67PCh. 12 - Prob. 12.68PCh. 12 - Prob. 12.69PCh. 12 - Prob. 12.70PCh. 12 - Prob. 12.71PCh. 12 - Prob. 12.72PCh. 12 - Prob. 12.73PCh. 12 - Prob. 12.74PCh. 12 - Prob. 12.75PCh. 12 - Prob. 12.76PCh. 12 - Prob. 12.77PCh. 12 - Prob. 12.78PCh. 12 - Prob. 12.79PCh. 12 - Prob. 12.80PCh. 12 - Prob. 12.81PCh. 12 - Prob. 12.82PCh. 12 - Prob. 12.83PCh. 12 - Prob. 12.84PCh. 12 - Prob. 12.85PCh. 12 - Prob. 12.86PCh. 12 - Prob. 12.87PCh. 12 - Prob. 12.88PCh. 12 - Prob. 12.89PCh. 12 - Prob. 12.90PCh. 12 - Prob. 12.91PCh. 12 - Prob. 12.92PCh. 12 - Prob. 12.93PCh. 12 - Prob. 12.94PCh. 12 - Prob. 12.95PCh. 12 - Prob. 12.96PCh. 12 - Prob. 12.97PCh. 12 - Prob. 12.98PCh. 12 - Prob. 12.99PCh. 12 - Prob. 12.100PCh. 12 - Prob. 12.101PCh. 12 - Prob. 12.102PCh. 12 - Prob. 12.103PCh. 12 - Prob. 12.104PCh. 12 - Prob. 12.105PCh. 12 - Prob. 12.106PCh. 12 - Prob. 12.107PCh. 12 - Prob. 12.108PCh. 12 - Prob. 12.109PCh. 12 - Prob. 12.110PCh. 12 - Prob. 12.111PCh. 12 - Prob. 12.112PCh. 12 - Prob. 12.113PCh. 12 - Prob. 12.114PCh. 12 - Prob. 12.115PCh. 12 - Prob. 12.116PCh. 12 - Prob. 12.117PCh. 12 - Prob. 12.118DPCh. 12 - Prob. 12.119DPCh. 12 - Prob. 12.120DPCh. 12 - Prob. 12.121DPCh. 12 - Prob. 12.122CPCh. 12 - Prob. K12.1KPCh. 12 - Prob. K12.2KP
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