The principle by which shape-memory alloys shows a memory effect needs to be explained. Concept introduction: An alloy when heated to its predeformed shape, shape memory of an alloy is formed. Parts are very lightweight whenever they are manufactured from shape memory alloy.alternatives to standard actuators such as hydraulic, pneumatic, and motor-based devices. Shape alloy also called as memory alloy, intelligent alloy because the mixutre present in the alloy is very precisely maintained.

Question

Want to see the full answer?

Answer 1

Question

Chapter 12, Problem 12.115P

Interpretation Introduction

Interpretation:

The principle by which shape-memory alloys shows a memory effect needs to be explained.

Concept introduction:

An alloy when heated to its predeformed shape, shape memory of an alloy is formed. Parts are very lightweight whenever they are manufactured from shape memory alloy.alternatives to standard actuators such as hydraulic, pneumatic, and motor-based devices. Shape alloy also called as memory alloy, intelligent alloy because the mixutre present in the alloy is very precisely maintained.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

The net force exerted on the piston by the exploding fuel-air mixture and friction is 5 kN to the left. A clockwise couple M = 200 N-m acts on the crank AB. The moment of inertia of the crank about A is 0.0003 kg-m2 . The mass of the connecting rod BC is 0.36 kg, and its center of mass is 40 mm from B on the line from B to C. The connecting rod’s moment of inertia about its center of mass is 0.0004 kg-m2 . The mass of the piston is 4.6 kg. The crank AB has a counterclockwise angular velocity of 2000 rpm at the instant shown. Neglect the gravitational forces on the crank, connecting rod, and piston – they still have mass, just don’t include weight on the FBDs. What is the piston’s acceleration?

A single-angle tension member of A36 steel must resist a dead load of 35 kips and a live load of 84 kips. The length of the member is 18 feet, and it will be connected with a single line of 1- inch-diameter bolts, as shown in the figure below. There will be four or more bolts in this line. For the steel Fy = 36 ksi and F₁ = 58 ksi. Try the tension members given in the table below. Tension member rz (in.) A, (in.²) L6 × 6 × 9.75 1.17 L 5 × 3 × 1/10 4.93 0.746 L5 × 3 × 16 5 2.56 0.758 L5 × 3 × 166 3.31 0.644 Bolt line a. Select a single-angle tension member to resist the loads. Use LRFD. A) L 6 × 6 × B) L 5 × 3 × C) L5 × 3 X D) L 5 × 3 × 6 -Select- V What is the required gross area? (Express your answer to three significant figures.) Ag = in.2 What is the required effective area? (Express your answer to three significant figures.) Ae = in.2 What is the minimum radius of gyration? (Express your answer to three significant figures.) 1min = in. b. Select a single-angle tension member to…

In the connection shown in the figure below, the bolts are 15/8-inch in diameter, and A36 steel is used for all components: Fy = 36 ksi, Fu = 58 ksi. 21/2" 11½½" 3". -3"- 料 11/2" 11/2" О О t = 3/8 31/2" О О t = 7/16 Consider both the tension member and the gusset plate and compute the following: a. the design block shear strength of the connection (Express your answer to three significant figures.) Rn = kips b. the allowable block shear strength of the connection (Express your answer to three significant figures.) Rn/= kips