Chapter 11.6, Problem 69AYU

In Problems 65-70, graph each equation and find the point(s) of intersection, if any.

$y=\frac{4}{x-3}$ and the circle $x^2-6x+y^2+1=0$

To determine

To graph: Each equation and find points of intersection.

Answer to Problem 69AYU

Explanation of Solution

Given:

$y = \frac{4}{x - 3}$    -----(Eq 1)

$x^2 - 6x + y^2 + 1 = 0$    -----(Eq 2)

Graph:

It can be seen from the graph that the curves touch at $(1,\text{-}2)$ and $(5,2)$.