Chapter 11.1, Problem 32AYU

To determine

To find: The solution of the given system of equations.

Answer to Problem 32AYU

Solution:

  $x=\frac{1}{5},y=\frac{3}{10}$

Explanation of Solution

Given:

  $3x-2y=0$

  $5x+10y=4$

Calculation:

The system of equations is:

  $3x-2y=0$

  $5x+10y=4$

From the first equation we get,

  $2y=3x$

  $y=\frac{3}{2}x$

Substituting $y=\frac{3}{2}x$ in the second equation we get,

  $5x+10\left(\frac{2}{2}x\right)=4$

  $5x+15x=4$$x=\frac{4}{20}$

  $x=\frac{1}{5}$

Substituting $x=\frac{1}{5}$ in the first equation we get,

  $3\left(\frac{1}{5}\right)-2y=0$

  $\frac{3}{5}-2y=0$

  $2y=\frac{3}{5}$

  $y=\frac{a}{5(2)}$

  $y=\frac{3}{10}$

Thus $x=\frac{1}{5},y=\frac{3}{10}$ is the solution of the given system of equations.