Chapter 11, Problem 6CT

To determine

To find: The system of equation of matrix $\left(\begin{array}{ccc}3& 2& 4\\ 1& 0& 8\\ -2& 1& 3\end{array}\right)\left(\begin{array}{c}-6\\ 2\\ -11\end{array}\right)$ .

Answer to Problem 6CT

The system of the equation is $\left\{\begin{array}{c}3x+2y+4z=-6\\ x+8x=2\\ -2x+y+3z=-11\end{array}\right\}$ .

Explanation of Solution

Given information:

The given matrix is $\left(\begin{array}{ccc}3& 2& 4\\ 1& 0& 8\\ -2& 1& 3\end{array}\right)\left(\begin{array}{c}-6\\ 2\\ -11\end{array}\right)$ .

Calculation:

Calculate the matrix,

  $\left(\begin{array}{ccc}3& 2& 4\\ 1& 0& 8\\ -2& 1& 3\end{array}\right)\left(\begin{array}{c}-6\\ 2\\ -11\end{array}\right)$

Therefore, the three variables are $x$ , $y$ and $z$ .the system of equations can written as $\left\{\begin{array}{c}3x+2y+4z=-6\\ x+8x=2\\ -2x+y+3z=-11\end{array}\right\}$ .