Chapter 11.3, Problem 7AYU

$\left[\begin{array}{l}\begin{array}{cc}6& 4\end{array}\\ \begin{array}{cc}-1& 3\end{array}\end{array}\right]$

To determine

To find: The value of the determinant $\left|\begin{array}{cc}6& 4\\ -1& 3\end{array}\right|$.

Answer to Problem 7AYU

22

Explanation of Solution

Given:

$\left|\begin{array}{cc}6& 4\\ -1& 3\end{array}\right|$

Formula used:

To find the value of a second order $2\times 2$ determinant:

$\left|\begin{array}{cc}a& b\\ c& d\end{array}\right|=a\times d-b\times c=ad-bc$

Calculation:

$D=\left|\begin{array}{cc}6& 4\\ -1& 3\end{array}\right|=6\times 3-4\times \left(-1\right)=18+4=22$