Chapter 11.6, Problem 55AYU

Graph the equations given in Example 4.

Solve: $\{\begin{array}{l}{x}^2\text{ + }x\text{ + }{y}^2-\text{ 3}y\text{ + 2 = 0}\\ x\text{ + 1 + }\frac{y^2-y}{x}\text{ = 0}\end{array}$

To determine

To graph: The equations.

Answer to Problem 55AYU

Explanation of Solution

Given:

$x^2 + x + y^2 - 3y + 2 = 0$    -----(Eq 1)

$x + 1 + \frac{y^2 - y}{x} = 0$   -----(Eq 2)

Graph:

It can be seen from the graph that the curves for the equations intersect at $(0,1)$ and $(\text{-}1,1)$.