Chapter 11.1, Problem 55AYU

To determine

To find: The dimensions of a rectangular floor if the length is twice the width and the perimeter of the floor is 90 feet.

Answer to Problem 55AYU

Solution:

Length $=30$ feet; Width $=15$ feet.

Explanation of Solution

Given:

Length is twice the width of the rectangular floor.

Perimeter $=90$ feet.

Calculation:

Let the width of the rectangular floor be $x$ feet.

Then the length of the floor is 2x feet.

Perimeter of the floor $=90$ feet.

We know that in a rectangle,

Perimeter $=2\times ($ length + width )

Thus we get,

  $2\times (2x+x)=90$

  $2\times 3x=90$

  $6x=90$

  $x=\frac{90}{6}$$x=15$

Therefore the width of the rectangular floor is 15 feet.

Then the length of the rectangular floor becomes = $2\times 15=30$ feet.

Hence the dimensions, that is, the length and width of the rectangular floor are 30 feet and 15 feet respectively.