Explain in your own words what a linear programming problem is and how it can be solved.
What is linear programming problem and how it can be solved.
Answer to Problem 32AYU
Solution:
All LP problems have the following general form:
Where decision variable.
objective function coefficient corresponding to the variable.
the coefficient on in constraint , and
the right-hand-side coefficient on constraint .
Step-1: Formulating the problem – Involves deducing the objective function and constraints equation.
Step-2: Solving the system of inequalities and obtaining the range of values (corner points) for decision variables. This can be done using graphical or computer programmes.
Step-3: Substituting the corner points in the objective functions and finding the values of maximum/minimum values of the objective function.
Explanation of Solution
Linear Programming:
Linear Programming (LP) is a mathematical technique for determining optimal solutions to problems that can be expressed using linear equations and inequalities. When real-world problems are represented accurately as a set of the linear equations, Linear Programming finds the best solution to the problems.
A linear program consists of a set of variables, a linear objective function indicating the contribution of each variable to the desired outcome, and a set of linear constraints describing the limits on the values of the variables. The solution to a linear program is a set of values for the problem variables that results in the best (either largest or smallest ) value of the objective function and yet satisfies all the constraints. Formulation is the process of translating a real-world problem into a linear program. Once a problem has been formulated as a linear program, it can be solved by analytical, graphical or using computer software.
Definitions in Linear Programming:
Linear Equations: All of the equations and inequalities in a linear program must, by definition, be linear. A linear function has the following form:
Where,
a. a’s are called the coefficients of the equation; they are also sometimes called parameters. The important thing to know about the coefficients is that they are fixed values, based on the nature of the problem being solved.
b. x’s are called the variables of the equation; they are allowed to take a range of values within the limits defined by the constraints.
Decision Variables: The variables in a linear program are a set of quantities that need to be determined in order to solve the problem; i.e., the problem is solved when the best values of the variables have been identified. The variables are sometimes called decision variables because the problem is to decide what value each variable should take. Typically, the variables represent the amount of a resource to use or the level of some activity.
Objective Function: The objective of a linear programming problem is to maximize or to minimize some numerical value. The objective function indicates how each variable contributes to the value to be optimized in solving the problem. The objective function takes the following general form:
objective function coefficient corresponding to the variable.
decision variable.
The coefficients of the objective function indicate the contribution to the value of the objective function of one unit of the corresponding variable.
Constraints: Constraints define the possible values that the variables of a linear programming problem may take. They typically represent resource constraints, or the minimum or maximum level of some activity or condition. They take the following general form:
Where decision variable.
the coefficient on in constraint , and
the right-hand-side coefficient on constraint .
It should be noted that is an index that runs from 1 to m, and each value of corresponds to a constraint.
Solving General Linear Programming Problem
All LP problems have the following general form:
Where decision variable.
objective function coefficient corresponding to the variable.
the coefficient on in constraint , and
the right-hand-side coefficient on constraint .
Step-1: Formulating the problem – Involves deducing the objective function and constraints equation.
Step-2: Solving the system of inequalities and obtaining the range of values (corner points) for decision variables. This can be done using graphical or computer programmes.
Step-3: Substituting the corner points in the objective functions and finding the values of maximum/minimum values of the objective function.
Chapter 11 Solutions
Precalculus Enhanced with Graphing Utilities
Additional Math Textbook Solutions
Basic Business Statistics, Student Value Edition
University Calculus: Early Transcendentals (4th Edition)
Elementary Statistics (13th Edition)
Calculus: Early Transcendentals (2nd Edition)
A Problem Solving Approach To Mathematics For Elementary School Teachers (13th Edition)
- "P3 Question 3: Construct the accessibility matrix Passociated with the following graphs, and compute P2 and identify each at the various two-step paths in the graph Ps P₁ P₂arrow_forwardA cable television company estimates that with x thousand subscribers, its monthly revenue and cost (in thousands of dollars) are given by the following equations. R(x) = 45x - 0.24x2 C(x) = 257 + 13xarrow_forwardx³-343 If k(x) = x-7 complete the table and use the results to find lim k(x). X-7 x 6.9 6.99 6.999 7.001 7.01 7.1 k(x) Complete the table. X 6.9 6.99 6.999 7.001 7.01 7.1 k(x) (Round to three decimal places as needed.)arrow_forward
- (3) (4 points) Given three vectors a, b, and c, suppose: |bx c = 2 |a|=√√8 • The angle between a and b xc is 0 = 135º. . Calculate the volume a (bxc) of the parallelepiped spanned by the three vectors.arrow_forwardCalculate these limits. If the limit is ∞ or -∞, write infinity or-infinity. If the limit does not exist, write DNE: Hint: Remember the first thing you check when you are looking at a limit of a quotient is the limit value of the denominator. 1. If the denominator does not go to 0, you should be able to right down the answer immediately. 2. If the denominator goes to 0, but the numerator does not, you will have to check the sign (±) of the quotient, from both sides if the limit is not one-sided. 3. If both the numerator and the denominator go to 0, you have to do the algebraic trick of rationalizing. So, group your limits into these three forms and work with them one group at a time. (a) lim t-pi/2 sint-√ sin 2t+14cos ² t 7 2 2 2cos t (b) lim sint + sin 2t+14cos = ∞ t-pi/2 2 2cos t (c) lim cost-√sin 2t+14cos² t = t-pi/2 2cos t (d) lim t→pi/2 cost+√ sin t + 14cos 2cos ² t = ∞ (e) lim sint-v sin 2 t + 14cos = 0 t-pi/2 (f) lim t-pi/2 sin t +√ sin 2sin 2 t 2 t + 14cos t 2sin t cost- (g)…arrow_forwardThink of this sheet of paper as the plane containing the vectors a = (1,1,0) and b = (2,0,0). Sketch the parallelogram P spanned by a and b. Which diagonal of P represents the vector a--b geometrically?arrow_forward
- (1) (14 points) Let a = (-2, 10, -4) and b = (3, 1, 1). (a) (4 points) Using the dot product determine the angle between a and b. (b) (2 points) Determine the cross product vector axb. (c) (4 points) Calculate the area of the parallelogram spanned by a and b. Justify your answer. 1arrow_forward(d) (4 points) Think of this sheet of paper as the plane containing the vectors a = (1,1,0) and b = (2,0,0). Sketch the parallelogram P spanned by a and b. Which diagonal of P represents the vector ab geometrically? d be .dx adjarrow_forward(2) (4 points) Find all vectors v having length 1 that are perpendicular to both =(2,0,2) and j = (0,1,0). Show all work. a=arrow_forward
- For the following function, find the full power series centered at a of convergence. 0 and then give the first 5 nonzero terms of the power series and the open interval = f(2) Σ 8 1(x)--(-1)*(3)* n=0 ₤(x) = + + + ++... The open interval of convergence is: 1 1 3 f(x)= = 28 3x6 +1 (Give your answer in help (intervals) .)arrow_forwardFor the following function, find the full power series centered at x = 0 and then give the first 5 nonzero terms of the power series and the open interval of convergence. f(x) = Σ| n=0 9 f(x) = 6 + 4x f(x)− + + + ++··· The open interval of convergence is: ☐ (Give your answer in help (intervals) .)arrow_forwardLet X be a random variable with the standard normal distribution, i.e.,X has the probability density functionfX(x) = 1/√2π e^-(x^2/2)2 .Consider the random variablesXn = 20(3 + X6) ^1/2n e ^x^2/n+19 , x ∈ R, n ∈ N.Using the dominated convergence theorem, prove that the limit exists and find it limn→∞E(Xn)arrow_forward
- Calculus: Early TranscendentalsCalculusISBN:9781285741550Author:James StewartPublisher:Cengage LearningThomas' Calculus (14th Edition)CalculusISBN:9780134438986Author:Joel R. Hass, Christopher E. Heil, Maurice D. WeirPublisher:PEARSONCalculus: Early Transcendentals (3rd Edition)CalculusISBN:9780134763644Author:William L. Briggs, Lyle Cochran, Bernard Gillett, Eric SchulzPublisher:PEARSON
- Calculus: Early TranscendentalsCalculusISBN:9781319050740Author:Jon Rogawski, Colin Adams, Robert FranzosaPublisher:W. H. FreemanCalculus: Early Transcendental FunctionsCalculusISBN:9781337552516Author:Ron Larson, Bruce H. EdwardsPublisher:Cengage Learning