Chapter 11.1, Problem 31AYU

To determine

To find: The solution of the given system of equations.

Answer to Problem 31AYU

Solution:

  $x=1,y=1$

Explanation of Solution

Given:

  $2x-3y=-1$

  $10x+y=11$

Calculation:

The system of equations is:

  $2x-3y=-1$

  $10x+y=11$

Multiplying the second equation by 3 and adding with the first equation we get,

  $(2x-3y)+3(10x+y)=-1+3(11)$

  $2x-3y+30x+3y=-1+33$

  $32x=32$

  $x=\frac{32}{32}$

  $x=1$

Substituting $x=1$ in the first equation we get,$2(1)-3y=-1$

  $2-3y=-1$

  $-3y=-1-2$

  $-3y=-3$

  $y=\frac{-3}{-3}$

  $y=1$

Thus $x=1,y=1$ is the solution of the given system of equations.